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11+32243])OH()NH(Co[2])NH)(NO(PtCl[2322+2432])NH(PtI[4−])OC()OH(Co[242225])NH(IrCl[3331acis-+32243])OH()NH(Co[btrans-+32243])OH()NH(Co[2acis-])NH)(NO(PtCl[232btrans-])NH)(NO(PtCl[2323acis-+2432])NH(PtI[btrans-+2432])NH(PtI[4acis-−])OC()OH(Co[24222btrans-−])OC()OH(Co[242225a])NH(IrCl[333b])NH(IrCl[3332.(B.M.)?1CuCl2-()2Zn(NH3)42+()3Co(NCS)42-()CuCl2-:Cu+3d4s4pCuCl2-3d4s4p[]sp(Cl-))2n(n+=0BMZn(NH3)42+Zn2+3d4s4pZn(NH3)42+3d4s4p[]sp3)2n(n+=0BMCo2+Co(NCS)42-3d4s4p3d4s4p[]sp3n=3)2n(n+3.87BM3+262])OH(Co[−46])CN(Mn[+263])NH(Ni[.M.B/µ4.31.83.111[Co(H2O)6]2+=4.3BM)2n(n+Co2+32[Mn(CN)6]4=1.8BM)2n(n+Mn213[Ni(NH3)6]2+=3.11BMNi2+24.??Co(en)32+Fe(C2O4)33-Co(edta)-B.M.3.825.750Co(en)32+Co2+(d7),=3.82B.M.)2n(n+n=3,enCo2+6Co(en)32+3d4s4p4d[]sp3d2(en),Fe(C2O4)33-Fe3+(d5),=5.75B.M.,)2n(n+n=5,Fe3+6Fe(C2O4)33-3d4s4p4d[]sp3d2(C2O42-),Co(edta)-Co3+(d6),=0B.M.)2n(n+Co3+6Co(edta)-3d4s4p[]d2sp3(edta4-),5−24]NiCl[2−24])CN(Ni[[NiCl4]2[Ni(CN)4]2[NiCl4]2Ni2+2()222+×=2.83B.M.[Ni(CN)4]2+=06B.M.1+263])NH(Ru[2−36])CN(Fe[3+262])OH(Ni[4+33])en(V[5−24]CoCl[1t2g6eg00)2n(n+=02t2g5eg01)2n(n+=1.73B.M.3t2g6eg22)2n(n+=2.83B.M.4t2g2eg02)2n(n+=2.83B.M.5t2g5eg23)2n(n+=3.87B.M.7dd1+2Fe2+3Fe3+2Ni4+2Zn5+2Co1Fe2+2Fe3+8.(0)(P)degt2g(B.M.)Co(NH3)62+Fe(H2O)62+Co(NH3)63+P/cm-12250017600210000/cm-1110001040022900Co(NH3)62+P0Co2+d,Co2+d7geg2t3)2n(n+=3.87B.M.Fe(H2O)62+P0Fe2+dFe2+d6geg2t4)2n(n+=4.90B.M.Co(NH3)63+0PCo3+d,Co3+d6geg2t0)2n(n+=0B.M.9.8Co(NH3)62+:(t2g)5(eg)2CFSE=n1(530)+n2(-520)=2(530)+5(-520)=0.80CFSE=0.811000=8800cm-1Fe(H2O)62+(g2t)4(ge)2CFSE=2(530)+4(-520)=0.40CFSE=0.410400=4160cm-1Co(NH3)63+:(g2t)6(ge)0CFSE=[0(530)+6(-520)]+(31)P=2.40+2PCFSE=2.422900+221000=12960cm-110.Fe(CN)64-Fe(NH3)62+05.2B.M.()Fe(CN)64-Fe(CN)64-3d4s4p[]d2sp3(CN-)d2sp3)2n(n+=0B.M.CN-Fe2+dgeg2t=0Fe(NH3)62+=5.2B.M.)2n(n+n=4Fe(NH3)62+3d4s4p4d[]sp3d2sp3d2NH3:n=4Fe2+dgeg2t11g2tged1−362])NO(Co[2+362])OH(Fe[3−36]FeF[4+363])NH(Cr[5])CO(W[6CFSE=(4n1+6n2)Dq+(m1m2)P/CFSE[Co(NO2)6]3t2g6eg0024Dq+2P[Fe(H2O)6]3+t2g3eg250[FeF6]3t2g3eg250[Cr(NH3)6]3+t2g3eg0312Dq[W(CO)6]t2g6eg0024Dq+2P
本文标题:化学课后答案11
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