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复数综合练习题1.(2011全国新课标)复数2+12ii的共轭复数是()A.35iB.35iC.iD.i2.(2011北京)复数212ii=()A.4355iB.4355iC.iD.i3.(2011江西)若12izi,则复数Z()A.2iB.2iC.2iD.2i4.(2011安徽)设i是虚数单位,复数12aii为纯虚数,则实数a为()A.2B.-2C.12D.125.(2011山东)复数2-2izi在复平面内对应的点所在象限为()A.第一象限B.第二象限C.第三象限D.第四象限6.(2011湖南)若,abR,i是虚数单位,且()aiibi,则()A.1,1abB.1,1abC.1,1abD.1,1ab7.(2011广东)设复数z满足(1)2iz,则z=()A.22iB.22iC.1iD.1i8.(2011天津)复数131izi()A.2iB.2iC.12iD.12i9.(2011福建)i是虚数单位,若集合1,0,1S,则()A.iSB.2iSC.3iSD.2Si10.(2011江苏)设复数z满足(1)32izi,则z的实部是11.(2011浙江)若1zi,则(1+z)z=()A.3iB.3iC.13iD.312.(2011辽宁)a为实数,2aii,则a=()A.3B.2C.2D.113.(2011陕西)设集合221{cossin,},{2,}MyyxxxRNxxxRi,则MN=()A.(0,1)B.(0,1]C.[0,1)D.[0,1]14.(2010江苏)设复数z满足(23)64zii,则z的模为15.(2010山东)已知2(,)aibiabRi,则ab()A.1B.-1C.2D.316.(2010广东)若复数121,3zizi,则12zz=()A.42iB.2iC.22iD.3i17.(2010安徽)33ii()A.13412iB.13412iC.1326iD.1326i18.(2010天津)1+312ii()A.1iB.55iC.55iD.1i19.(2010辽宁)设,ab为实数,若复数121iiabi,则()A.31,22abB.3,1abC.13,22abD.1,3ab20.(2010全国新课标)已知复数23(13)izi,则zz()A.2B.1C.12D.1421.(2011陕西)复数1izi在复平面内对应的点所在象限为()A.第一象限B.第二象限C.第三象限D.第四象限22.(2011上海)已知复数1z满足1(2)(1)1zii,复数2z的虚部为2,且12zz是实数,求2z.
本文标题:复数练习题
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