试用积分法求图示各梁的转角方程和挠度方程

8-1AC(c)PRB=PlMB23=8-3vf(x)8-68-9EIaqyc84=c8-17823BCEIGIP1ACCPMPlPEIplyc331=MρϕGIpllyc22==2BCEIplyB33=ρGIplEIplyyyvBccB332132+=++=828A1BA2CEIYCvB1A1BA1BPYcP))(3(6121/1↓−=llEIplvcYc)(321//1↑=EIlYvcc//1/11cccvvv−=∴A2C)(3212↓=EIlYvcc21ccvv=∴114)3(lllpYc−=2P)(321↓=EIplvBYc))(3(61211↓−=llEIlYvcB)3(63121321llEIlYEIplvvvcBBB−−=−=∴8-30ABDG18BCd20mmE200GPaP30kNCCBCNABN∴cPPN=−:CBvv−=∆l1.4NlEA∆=()348CPNvEI−⋅=33BNvEIα=∴()41.4833PNNNEIEAEI−⋅=+∴9.82NK=N3max69.82102106.118510ABazNABMPWσ−⋅××===×3max269.821031.31010BCaAMPNσπ−×===⋅×()()3max6111309.82104224109.118510DGazPNDGMPWσ−−⋅−×××===×109.1aMP31.3aMP()()333934309.82104108.1484820010166010aPNDGvmmEI−⋅−×××===××××8-31