戴维南等效电路参数的求解

:ocuocN+i=0NoRo1(1)Uoc(2)Ro()(3)2Rx1.2Ω5.2ΩIIRxab+–10V4Ω6Ω6Ω4ΩRx.ab+–10V4Ω6Ω6Ω–+U24Ω+–U1IRx+Uoc_(1)Uoc=U1+U2=10×4/(4+6)+10×6/(4+6)=4+6=2V(2)ReqReq=4//6+6//4=4.8ΩIabUoc+–RxReq(3)Rx=1.2ΩI=Uoc/(Req+Rx)=0.333ARx=5.2ΩI=Uoc/(Req+Rx)=0.2AscocIUR=0(Uoc=0)IURs=03(1)UocUoc=10(V)105.01000)10001000(=×−+scscII(2)Ro())(1501AIsc=)(15000Ω==scocIURIIIIU′=′+′−′=′15001000)5.0(1000Q)(15000Ω=′′=∴IUR:iu~(VCR):BiAu+=+_uiuOCR0u=8+4iΩ==480RVuOC+_510V20i1i`+u:);00RLCR=•=ττ02max4RuPocL=