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123411234A.B.C.D.E.F.190O234Au100561C2F3E4A5C6D150Hz210kHz12kHz3412341T7.4kT7.4abI3142O2O43'O43I12O2O1OI343421f2I21I1fO1)b(d1)1()()a(uRkRRRukuRRuRRuRRutuRCuuRRRRRRRuRuRu⋅=⋅−=−=−=−=⋅+⋅+++−=∫27.11234112347.21Au12Au034YaX1bX2cX3abc5YaX1bX2cX3abc6YaX212345637.3P7.314VP7.3uI/V0.10.51.01.5uO1/VuO2/VuO1(Rf/R)uI10uIuO2(1+Rf/R)uI11uI14V14VuI/V0.10.51.01.5uO1/V151014uO2/V1.15.511147.4Ri20k100P7.3(a)R20kRf2M7.5P7.512Ri50kuM2uI342RRRiii+=3OM4M2MRuuRuRu−+=−uP7.5IMO10452uu−==47.6P7.514VuI2V1R22R33R44R41V42I13O−=−=−=uRRu2V42I12O−=−=−=uRRu3uO14V4V84I132O−=−=+−=uRRRu7.7P7.7T1T2T31I1mAI2mA2I30.2mAR3kP7.7110.421057.8P7.8P7.8a13I2I1I33fI22fI11fO522uuuuRRuRRuRRu+−−=⋅+⋅−⋅−=b13I2I1I33fI22fI11fO1010uuuuRRuRRuRRu++−=⋅+⋅+⋅−=c)(8)(I1I2I1I21fOuuuuRRu−=−=dI44fI33fI22fI11fOuRRuRRuRRuRRu⋅+⋅+⋅−⋅−=1413I2I1402020uuuu++−−=7.9P7.867.10P7.8aI3ICuu=bI3I2I3322I2323IC1111110uuuRRRuRRRu+=⋅++⋅+=cI2I2f1fIC98uuRRRu=⋅+=dI4I3I4433I3434IC4114140uuuRRRuRRRu+=⋅++⋅+=7.11P7.11P7.116.02Z2PL===RURuImA77.12P7.121uOuI1uI22RWuI110mVuI220mVuO3uO14VuI1max10mVuI2max20mV0VR2P7.121A2)(10)(I1I2I1I2fN2P2uuuuRRuu−=−==))(1(10)1(I1I212P212OuuRRuRR−+=⋅+=u)(10I1I21WOuuRRu−⋅⋅=2uI110mVuI220mVuO100mV3()I1I2uu−20mVR1)I1u(I2u−20mV14V14201010)(10min1I1I2min1WO=⋅⋅=−⋅⋅=RuuRRuR1min143R2maxRWR1min100.143k9.86k87.13P7.13P7.13abA1A2cA1A2A3A4aR3R4R5M))(()(2I21I15434344MO5M2I21I15342I21I13MRuRuRRRRRRiuuRuRuRuiiiRuRuRuRRRR+++−=−=−+=−=+−=buO1uO9))(1()1()1()1()1(I1I245I245I11345I245O145OI113O1uuRRuRRuRRRRuRRuRRuuRRu−+=+++−=++−=+=cA1A2A3uI1uI2uI3A4)(10)(I3I2I1I3I2I114OuuuuuuRRu++=++=7.14P7.14auIbt0uO0uOP7.14)(d11OIO21tutuRCutt+−=∫uI)()(100)()(10101)()(11O12I1O12I75112IOtuttututtututtuRCuO+−=+−×−=+−−=−t0uO0t5msuO10055103V2.5V10t15mSuO[100(5)101032.5]V2.5VP7.14P7.147.15P7.15uIP7.4bt0uO0uOP7.15P7.15uO100uIt2t1uIuCt1P7.15117.16P7.16P7.16atuutuCRuRRd100d1III1I12O∫∫−−=−−=ubII3I21I1O2dd10ddutuuCCtuRC−−=−−=−uctutuRCd10d1I3IO∫∫==udtuutRuRuCd)5.0(100d)(1I2I12I21I1O+−=+−=∫∫u7.17P7.17R1RR'100kR2Rf100k12C1FP7.171uOuI2t0uO0uI1V6V1A1uCuOIOO2fI1fO1uuuRRuRRu−=⋅+⋅−=RuRuuiIOO1C−=−=tutuRCtiCud10d1d1IICO∫∫∫−=−==2uO10uIt1[101t1]V6Vt10.6S0.66V7.18P7.1813P7.18A2uO2R1CA2uO∫∫∫−==+=−=−=tuuuuRRtutuCRud2)1(d2d1IOOO32O2II1O2u7.19P7.19uI14VuI21VP7.191SABCDuO2t0SuO0141UA7VUB4VUC1VUD2VuO2UD4V2uO2uDuO32uD4VuO34VuOmS6.28471010501163A1O3≈−=××××−=⋅⋅−=−tttuCRu7.207.207.207.21P7.2112uOuI1uI2P7.211A215)1.0(I2Of'OfI1I2O'OuuRRRuRRRuukuu−⋅+=+==I21IfO)(10uuRRRu⋅+−=7.22P7.22P7.22ab)()()a(2I21I1I33OI3O2I21I13'ORuRukuRuukuRuRuRu+−==+−=16I143I2342I24O)buRRukRRkuRRu−−−=(7.237.3.9557.3.9N55N0.257.24150Hz21Hz32kHz4100kHz1234177.25P7.25P7.25abcd187.26LPFHPF22kHz100Hz2kHz100Hz4p=uA&12lg20p≈uA&P7.26P7.267.27P7.27P7.2719a11)(1212CsRCsRsCRRsAu+−=+−=bCsRRRRsCRsCRsAu21212211)1(1)(+⋅−=+⋅−=7.28P7.28uO1uO2uO3LPFHPFBPFBEFP7.28uO1uO2uO3207.29P362P3637.307.4.921kHzC1F2p=uA&21P==ffuAQ&RCffπ21p0==Ω≈k160RΩ≈==k640421RRR21
本文标题:信号的运算及处理习题及解答
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