工程热力学第三版电子教案第2章

22.1.........................................................................72.2....................................................................................72.3............................................................................................72.4.......................................................................122.5.......................................................................................142.12.2123,2.31mRTPVP2mRTPV3a222111TvPTvPb222111TVPTVPab1111RTmvp2222RTmvp21mmab45L101325Pa0.1L,25,25250.1L=2.5L,;50500.lL=5.0L???,,,,,,5Vpp0pp0T0pdmdmddmp0pppmm0dddd1dpdmpV=mgRTVdp+pdV=gRmdT+gRTdmpV=mgRTmmTTVVppdddddV=0dT=0mmppdd212pVTRppmppppgd)(d)(d000d)(dd0000VTRpppppppgp=0pVTRpppg000lnVTRppg00exp161m32.11002barN2201barCO21T1p31TQ=0W=0U=0TnCTCnTCnVMCOCOVMcoNNVMN0220222020,,0,,T=max0,,0,0,,22022202VCOCOVMCONNVMNCTCyTCy0645.02938314110250,0,0,2222NMNNNTRVpnkmol0410.02938314110150,0,0,2222COMCOCOCOTRVpnkmol1055.00410.00645.022CONnnnkmol611.01055.00645.022nnyNNkmol389.01055.0410.022nnyCOCOkmol77.2020,NVMCkJ/kmolK88.2820,COVMCkJ/kmolK925.2388.28389.077.20611.0202202,,COVMcoNVMNVMonCyCyCkJ/kmolN21002bar1m3CO2202bar1m32.1KT=925.2329388.28389.037377.20611.0=335.43K2pp=22CONMmMVVTnRVTnR=243.33583141055.0=1.471105Pa=1.471bar30,0,,222202lnlnNNMNNpMNMpyRTTCynS0,0,,222202lnlnCOCOMCOCOpMCOpyRTTCy08.2920,NpMCkJ/kmolK19.3720,COpMCkJ/kmolK2471.1611.0ln314.837343.335ln08.29611.01055.0MS1471.1611.0ln314.829343.335ln19.37389.0=1.055[0.611(-3.0873+0.6501)+0.389(5.0296+4.6411)]=0.6265kJ/K1U=02,3S=02.4115.24cm7.6bar2.25g272345,(0.5-0.6Mpa,40-60),15kg,.6Ctb25bp=1barvp=0.2barCt1601Ct702903cm153cm794000Pa5%1148u-vu-pu-T9uhuT100Tvu0Tpu11cpcv12kkbTcv0kT133m3pc1=50kPapc2=0.3Mpat1=45t2=70pc=0.1Mpa149.5m30.1Mpa200.2m3201bar0.8Mpa20153m344p1=8bart1=47p2=3bart2=27121bar17162.2020101021030170.4Mpa0.1m30.15MPa0.1m3252.22H2H2518p01=50KPap0=103kPa192501002014.6Mpa601m30.06m3702.51,,()2p-v()3,()4surp,dv,W=surpdv5vpCC=R()6,()7,()8()9CpCvT,Cp-CvT1013m1C,()1A)B)C)2()A)B)C)3A)B)C)D)4()A)B)C)D)5vpMCMCA)B)C)D)1__________23,,4igir5,125C,0.1Mpa23m,8.53m20250cm2bar,18C0.23m200C350kg75kg2cog=0.142og=0.06OHg2=0.052Ng=0.752og=0.2322Ng=0.768P=1bar,T=300K