人教版七年级数学上册各章知识点总结及对应章节练习

1+10-1020000/2121234534abab1a+b=0ab0+0=0002aba+b=0-aaabab-10a=a22aa1aaa212003000aaaaaa000aaaaa00aaaaa3.,004.0aaaaa10aaaaa-15.abdd|a-b|6.220abcdabcd1ab=1ab0002abab=13450a1aa000,,,,aaaa000000432332310101111,1,1,1,1nnnaann.1)02):.3):4):0.ab,a-b0;a=b,a-b=0;ab,a-b0.0.10110,naana,na1=4101=810XXX0aaQQQ,,,,,12345abababababab11A+2ab.B.23bca2325ab.9x42x3xy-4....++X=X=X012=3122a=b,3a+2=2b+3.(),a=b,3a-2=3b-2.(),-2a+3=-2b+3,a=b.()ax=ay,x=y.()a=b,xa+y=xb+y.()xa+y=xb+y,a=b.().05=4+1222abab1xy210xx1x13xx4322x211x8.x..ax=ba0;10;1234567812345678910111213141516MABAMBM.=12ABOMAOB,12AOMMOBAOB1.A.B.0C.D.2.+3+-3-+5C.+-7--7-2-23.ab,()A.a+b0B.a-b0C.0abD.0ab4.A3A47AB.6665.2000-2001+2000-20016.-aaA.B.C.D.7.()A.B.C.D.8.cba0cbacba,,A.B.C.D.9.b+32+a-2=0ba10.1011.abab0a+b0AabBabCabDab012.2a(2)3aB.3D.313.|a|=2|b|=1ab0a+b-1-314.1ba,ab2a=b,a=b.322ba,ba.4ab,ab15.2562128264232216282422287654321202A.2B.4C.6D.816.x2y(y3)2=0x2xyy2B.27D.1217.2011(1)A.B.C.2003D.18.5x2yyxA.3B.77D.3719.a2=b2,()a=ba=?ba=?ba=b=0|a|=|b|a3=?b320.3322,2222,2222,2322()D.421.654321++19992000A.B.C.D.22.205.04A.1440B.3104.1C.41014.0D.2101423.5424.16712743-6020-23-43-813222121(3)24243342023)1(59)3(225.*baabba+=*,2*3*4.26.2)1(,22yx=4x+y1.yx23.0,0,21x,222abc,231x,y41,21312ab()A.2B.3,y0,yx,()+x+x+x3.A4ab4abcBmnmn23Cba232232abDyx2zx24.,()A.nnyx22nnxy(n)B.yx2523yx1D.ba21.022.0ab5.7)2(21xnxnxnA.2B.2C.22D.36.614212xx13642xx7.(x-3)2-2(x-3)-5(x-3)2+(x-3)(x-3)(x-3)2+(x-3)(x-3)2-x(x-3)(x-3)2-(x-3)(x-3)2-(x-3)8.1a+(b-c)=ab-c23a-(b+c-d)=3a-b+c-d34+2(a-b)=4+2a-b4x2--[--x+y+z]=x2+x-y+zA.1B.2C.3D.49.3a+2ba-bA.12a+6bB.7a+3bC.10a+10bD.12a+8b10.x2-2x4-7x2+1....11.1248162006A.20062B.122006C.20052D..12.853ab13.3xm-1y232xyn+1mn14.2323nmnmnmm15.2332464554132132yxyyxxyyxyxxy16.xx323132xx17.65baxyba362x3y=18.9)62(22babkaabk=19.k_______8213222xxyykxyxxy.20.,052yx3923252yxyx______________21.2x2(3xy2x2y)2(xy2x2)22.22225(3)2(7)abababab23.a5b3bababa2622224.3,21yx3(x2-2xy)-[3x2-2y+2(xy+y)].25.:A=x21,B=231yx,C=23123yx.2ABC1.x)1()3(2xbaxA2bB0bC0aD6ba2.75x94xx()A.29B.29C.92D.923.122313xxA1)2(3)13(2xxB3)2(3)13(2xxC6)2(3)13(2xxD2)2(3)13(2xx4.x=-3x52kkxkA.-1B.5C.-5D.315.96020%20%AB160C80D806.30A30B70C21D437.6503050A275B295C245D3258.A28B33C45D579.y=12yym2)(31xmx+4=m2x+4Ax=1Bx=1Cx=0D10.263.A39B42C45D4811.11A4B19C20D3012.8015010012013.100100202004016000A90%B85%C80%D75%14.25%1278ABCD115.04)2(1||axaa_________16.2xm3+3x=5m=17.0x1x2x_________11xx.18.x=_________3)1(2x9.19.m______45)12(3xx)2(2)1(2mmx.20.dnaan)1(131a2d21nan=_______21.3215________22.225%15%_________.(100%)23.2546xxx24.175321416181x.25.41.550.81.20.50.20.1xxx26.1.6122030xxxx27.x5)35(3)13(xaxa32)2(5axa.28.101215329.1201A2B1030.814%12001.ABCD2.A.B.C.D.3ABCD4.+=900,+=900,()A.B.C.D.=900+5.40504050406.7372A.B.C.D.7.ABCDAEDBCFBAF=60DAE=A15B30C45D608.AOEBOCODCOEAOEBOCA1B2C3D49.EFCDMNMFB=21MFE.MFB=A30B36C45D7210.35ABC125D11.O3050AO3580BAOBA65B115C175D18512.215230A30B45C60D9013.7,.14.ABAB=abc2?15.,DAB,EBC,BE=51AC=2cm,DE,DE.16.AOOCOBODCOD=38AOB.17.AOEAOB=40EOD=2846ODCOECOB18.2BOCAOCODAOB20CODAOB