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01.y=x24x+1y=2x2y=2x2+4xy=3xy=2x1y=mx2+nx+py=(4,x)y=x+1(x-1)-x22y=(m1)xm2+1+5x3my=a(xh)2+k3.1)3(22xyAB3xC1D3xyx42011245yxx2()yxhkyy=ax2+bx+c5.1y=12x22x+12y=3x2+8x2y=a(xh)2+kx=hh,k,ky=ax2+bx+cx=-b2a-b2a4ac-b24a,4ac-b24a6y=x2+2x37.y=3x2+mx3x1m8.y=x2-6x+cxc9yaxbyax2bxc()A.yB.yC.yD.y10.hth=5(t1)26A1B5C6D713.y=4x2mx+5x2,yxx2yxx1,y14.2()1yxmxlyxm15.y=12x2+3x+52A(x1,y1),B(x2,y2),C(x3,y3)3x1x2x3y1,y2,y3.16.223yxxy0xA1x3Bx1Cx3Dx1x317cbxxy21012yxx18.2yaxbxcyxx01234y41014A1x1yB2x2y112,x234x1y2yA12yyB12yyC12yyD12yyay=a(xh)2+kx19.y=32x234202011y=x22x3,4_______.abc21.y=ax2+bx+cabcA.a0,b0,c0B.a0,b0,c=0C.a0,b0,c=0D.a0,b0,c022.b0y=ax+by=ax2+bx+cxyO111,-2bxxy2-1112Oxy23.2yaxbxcABCOA=OC=1Aab=1Bab=1Cb2aDac024yax2bxc(a0)()Aa0Bb0Cc0Dabc04.yax2bxcyaxbcABCD25.2yaxbxcayxybx11y=ax2+bx+cx1030b2a=0abc0a2b+4c08a+c0A3B2C1D022yaxbxcy1,120ac0ab244acba0abc.()A.1B.2C.3D.44cxxy62A1y1B2y2C23y3y1y2y3A.y1y2y3B.y1y3y2C.y2y1y3D.y3y1y2OxyOyxAOyxBOyxDOyxC5)0(1knkxy)0(22acbxaxyA(15)B(92)xcbxaxnkx2A91xB91xC91xD1x9x2.y=ax2+bx-3a0xA-20B40yC12PAAB3BQBBC1CPBQPBQ3PBQBCKSCBKSPBQ=52K(1)y=x2-x-3(2)1,(3)K11-K23-1A-20B40y=ax2+bx-3a0y=x2-x-32tAP=3tBQ=tPB=6-3tC0-3RtBOCBC==51QQHABHQHCOBHQBOC=HQ=tSPBQ=PB?HQ=6-3t?t=t2+t=t-12+PBQ0t2t=1SPBQ=1PBQ3BCy=kx+ck0B40C0-3BCy=x-3KKmm2-m-32KKEyBCEEmm-3EK=m-3-m2-m-3=m2+mPBQSCBKSPBQ=52SPBQ=SCBK=SCBK=SCEK+SBEK=EK?m+?EK?4-m=4?EK=2-m2+m=m2+3mm2+3m=m1=1m2=3K11K2321ABCD1EFGHAE=BF=CG=DHEFGHsAExsxABCD2cbxxy2-101-2xCAC31000.4m0.5m()m2.201210ABOCOBACADODDACACE1DEO2AD=5AE=4O3.201210ABOAEOEOCDD1EACCABxy2O111,-2cbxxy2-1ABC32CD4AD8O4.201212ABODOADCDOAABEOFCE=CB1BCO2AFBFABF5.2012101OABCABODACCBD=BACODOE1BDO2EODOACE5xOyOABCOAOC12cm6cmACyxy=ax2+bx+cAB18a+c=012PAAB1cm/sBQBBC2cm/sCtPBQSSttSRPBQRR
本文标题:二次函数培优经典题
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