二次函数知识点+例题及其应用

1.1y=ax2+bx+cabca0yx2b=c=0y=ax21Ay=ax2+bx+cBCDy=x(x1)2m2.13_____________40_=52a0x=y=a0x=y=6y=m2x2-4x+1-3,m()A.1B.-1C.1D.7(0x3)()A03B10C13D18A=lBlClD3932A64B814C46D8144y=ax2+bx+cabca---a0a0c---Yyc0yc0c0bYabYaba+b+cx=1;ab+cx=11a+b+cxa+b+c01a+b+cxa+b+c0-1a-b+cxa-b+c0-1a-b+cxa-b+c0b+2a1b2a2a-b-1-11yx101a+b+c0a-b+c0abc0b=2aA1B2C3D431(1)yax2bxc(2)ya(xh)2k(3)ya(xx1)(xx2)11x2(2,8),12ABABC3,0.1303bx(10)(30)b4(1)y=ax2+bx+c(a0)mxax2+bx+c=m(ax2+bx+c-m=0),ax2+bx+c=0(a0)y=ax2+bx+c0x.(2)y=ax2+bx+c(a0)ax2+bx+c=0(a0).ax2+bx+c=0y=ax2+bx+cxb2-4ac0b2-4ac=0b2-4ac01415ABCD16y=x2+x+m,x,y0,m()A.m;B.m;C.m;D.m17x=1xAByCAC-1001.512PxABP3xQABQABP525xABABACC21ABAC2PACPyEPE269yax2ca0ABCDADxA2,0B1,3132MyMABM232PSPAD4SABMP4=*y,1x2x10155513xyw1yx2wx3124200?56wx