城市房屋拆迁补偿研究

华中科技大学硕士学位论文城市房屋拆迁补偿研究姓名：徐敏申请学位级别：硕士专业：管理科学与工程指导教师：仲景冰20080605I;;;;;IIAbstractTheactivityofhouseremovalandresettlement,whichisconcernedwithbenefitofcitizensandstabilityofthesocietyandthedevelopmentofthecountry’seconomy,hasexperiencedmorethan20years,withthetrendofincreasedurbanization.Forarealestatedevelopmentproject,thetaskofhouseremovalandresettlementisalsocrucial,whichwouldpossiblyharmtoinvestmentandscheduleandqualityofthewholeprojectifmanagerialjobhasnotbeendoneproperly.Asamatteroffact,thiskindofproblemisinclinedtobehappeningmoreduetocurrentenhancementofurbanization.Underthissocialcircumstance,thispaperaimstoreducecontroversyhappeningduringtheprocessofhouseremovalandresettlement.Firstly,thisthesisgivessomeintroductionaboutbasicknowledgeofhouseremovalandresettlement,mainlyconcernedwiththeusualprocessofhouseremovalandresettlementandtherelativehouseappraisalapproach.Secondly,itpointsoutthedeficiencyofhouseremovalandresettlementpolicyrelatedtocurrentsystemandmechanism.Furthermore,anewmechanismispromotedtocorrectthedeficiency.Thirdly,itanalyzesthedisadvantagesofcurrenthouseremovalandresettlementprinciplewhichcompensationsystemisbasedon.Plus,anewcompensationprinciplehasbeenbroughtupandalsoanewcompensationsystemwhichisestablishedonit.Lastly,thisthesismainlyfocusesonquantificationofthethreeinvisiblecompensationfactors,whichisestablishedinthenewcompensationsystem,byusingfuzzymathematicsmethod.Afterthequantificationofeachinvisiblefactor,apracticalcasehasalsobeengiventotestthenewmethodofcalculatingthecompensationprice.Andalso,thisthesishasgivensomesuggestionforthefuturerelativestudy.KeywordsUrbanhouseremovalandresettlement;Marketcomparisonappraisalapproach;Compensationpolicy;Compensationprinciple;Invisiblecompensationfactor;VisiblecompensationfactorI2008614_____20086142008614111.150%“”“”200326193%2004350200562220859.4%20052201-6826221113.4%2[1]1.21.2.112[2](1)(2)——(3)(4)3()[3]()[4]75%1.2.2(1)(2)(3)(4)(5)(6)(7)4(8)(9)30[5]1-1(1)(2)(3)“5”[6]1.2.31.2.4[7]6[8]1)(2)(3),;;[7]()“”()“”“”“”735[9]19911991199119912001199182001[10]200131[11]1.391234121-21022.1199120011112-111(1)(2)(3)(4)(5)122-12.1.1122.2.2(1)(2)(3)(4)(5)2.2.3132.2.414115216[12]2.22.2.1[13]20016640200111“”“”[15]172.2.2“”——[14]18[13]2.2.3=×2-1.“”=/2-2——“”=÷(=×)[16]19[17][18]2032001——3.13.1.124[19]A6010AA21500/2000/2500/A10003.1.212004920062007[20]22“”[21]2233.23.2.11[22]3-13-23-1243-22[18]25[23]3.2.21[24][25]226[26][27][28]3.2.33.1(1)(2)(3)[14]27[29][30]3.1“”——[31](1)[32](2)[33](3)[34]283-329420014.14.1.11[35]2“”(1)30(2)(3)2003(4)314.1.2[36]1(1)P=P1-P2(4-1)P——P1——P2——P11P12P13P14P1532P1=P11+P12+P13+P14+P15(4-2)(2)[37](3)P2=P1/N×N1(4-3)P1——P2——N——N1——58110[38]233(1)P=P1×K1×K24-4P——P1——K1——K2——4.1.32001125201525342002531105005002002717600[39]4.24.2.11887“”35“”“”[40]R=f(R1R2R3R4)(4-5)R——R1——R2——R3——R4——4.2.2“”1(1)(fuzzyset)36“”19“”“”1965“”37(2)XAuA:X→[0,1]u1AuA(x)XxAUA(x)1xAuA0xAuA(x)=0xA{}123,,...nXxxxx=12i12()()()....XAnAAnuxuxuxAXxxx=+++∈(4-6)“+”“”“”XA=0.9/0.5/0.2/A0.90.90.22“”“”4→→→→(1)38[41]RR1R2R3R44-110102020304040555539(2)V=v1,v2,……vn,vj(j=1,2…,n),jV=()0100.330.330.660.661(3)4-14-11231√2√3√4√5√6√7√8√9√10√∑30%30%40%400.30.30.4R1112131212223233132334414243rrrRrrrRRRrrrRrrr==4-7(4)A=a1,a2,a3,a4Ri0ai1,∑=niia1=1[42](5)ARB,[][]11121321222312341234313233414243brrrrrrrrBARaaaabbbrrrr===4-8biMaxbi3452310281017241R=0010100.20.800.10.70.2R1,R2,R3,R44-2aij1cicj3cicj5cicj7cicj9cicj2,4,6,81,1/2…1/9cicj4-3RR1R2R3R4R1131/55R21/311/73R35717R41/51/31/71RmaxRWWλ=maxλRWmaxλWiW[43]CICI=(maxλ-n)/(n-1)4-9CI=0maxλ-nCI42CIRI4-4RIn3456789101112RI0.580.891.121.261.361.411.461.491.521.54CIRICR=CI/RImaxλ=4.248CR=(4.248-4)/(4-1)=0.082,RI=0.89,CI=0.082/0.89=0.0920.1,(0.2080,0.0945,0.6419,0.0556):B=AR=(0.2080,0.0945,0.6419,0.0556)0010100.20.800.10.70.2=(0.1839,0.9970,0.3191)4.2.31[44]43[45]2P=A1+A211)1(1)1(nniii+−++A3+A422)1(1)1(nniii+−+(4-10)A1=a1*N1(4-11)A2=a2*N1(4-12)A3=a3*N2(4-13)A4=a4*N2(4-14)P——A1——A2——A3——A4——n1——min()n2——i——a1——a2——a3——44a4——N1——N2——31520a1=2*2*2=8()a2=2*10=20(10)a3=4a4=5N1=250250/N2=180n1=min(15,20)=15n2=5,i=10%,P=8×250+20×25015151.110.11.1−×+(4×180+5×180)551.110.11.1−×=59372.2(4-15)4.2.41(1)()45(2)1510246“”[46]3(1)47[47](2)012(1)(1)...(1)nSSKKK=+++(4-16)S——S0——K1K2…Kn——12…nn——4.2.5475-4901-1202007830200832.2.41(1):484-2(2)(3)(4)(5)554575704728532(6)(7)4994000m292000m22000m23785%100%4-350(8)(9)2(1)“”“”×(........)100×100(........)×(........)100×(........)100(4-17)511(1)niiiAVR==+∑(4-18)V——/m2Ai——/m2R——%N——(2)4-5a100/100b100/100c1004-6524-5ABCDEF200710200710200710200710200710200710-----90%90%85%85%80%85%4090/m24170/m24240/m24060/m24110/m2-----710/m2710/m2710/m2710/m2710/m2-----639/m2639/m2604/m2604/m2568/m2-----3451/m23531/m23636/m23456/m23542/m2-----534-6ABCDEF1001001001001001001001001001001001001001011011011011001001011021011011001001011021011011001001001001001001001001001001001001001001011011001001001001001001001001001001011011011011001001001001001001001001001001001001001001001001001001003451