机械设计计算公式及单位换算(能源动力单位)

[e-mail]1,3062321-36643312334:.K(Kelvin)degree=C(Celsius)degree+273.:1Kcal=4BTU=[e-mail]2:.:1Kcal=4BTU=4.18KJ.:1Kwh=3.49MJ=860Kcal..:1KW=0.24Kcal/s=0.96BTU/s=1.34hp.K(Kelvin)degree=C(Celsius)degree+273.=*g*(J).=*.(E,Energy)(P,Power)(t).(,Power)=*.=/,=*..=(2*G*)(m/s).=0.5**()^2.=*(Kg.m/s).=(*)/(N).=/(cm).[]=0.5*[/]*[].*[N.m]=()=*(Kg.m/s).(Drag)(F)(v);();().(N)=*/.(Joule)=0.5**(Rad/s).()=*/*.()=1.732**.*.=0.5**()^2.=0.5**()^2.=0.5**()^2.=**(Kcal).*=*.1r.p.s2/.=/.=-.=**.(Watt)=2*3.14*(Newton.meter)*(Rad/s).(Joule)=0.5*[.]*(Rad/s);E=0.5*I*w^2.(Watt)=2*3.14*(Newton.meter)*(Rad/s).PTq(2)n33000P(HP),Tq,nr.p.m.26.28.()=[.]*(Rad/s).=,[]([N.m]*[s]T*t=*I*w);(TtIw).=**[e-mail]3:.()=*/*(V)=(A)*()[Z,(Ohm.)]=[()^2+()^2]^(1/2)*.()=1.732**.*(p.f;powerfactor)//[p,(VA/KVA)]=*;([(VAR/KVAR)]*Sin..S=V*I=(P^2+Q^2)^(1/2);.Q1=Q0-QC.=0.5**()^2..;..1/2^2;.=0.5**()^2:BTU](hrkcal)]()E[(J)]=Qv[]*P[]*t[](Pump)EP[N/(Pa)]V[,(m^3)][e-mail][e-mail]5:[1],[2][3][4][5][6][7][8],,[9][10]--------------------------------------------------------------------------------------------------------------------()/e-mailLeanProductionLogistics()[e-mail][e-mail][e-mail][e-mail][e-mail][e-mail][e-mail][e-mail][e-mail][e-mail][e-mail][e-mail][e-mail]18