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抗拔力=700kN桩径=600mmC45配筋10φ250.3mmAS=4906.25mm2Ate=282600mm2σs=142.68MPa混凝土ES=31500MPaftk=2.51MPafc=21.1MPa钢筋ES=200000MPafy’=360MPafy=360MPaαcr=2.7cs=65mmνi=1.0=0.017取ρte=0.017=25.000=0.441取ψ=0.441=0.203mmωlim=0.3mm配筋:σs=142.68MPafy’裂缝:ωmaxωlim四、结论满足要求。满足要求。混凝土等级桩基抗拔裂缝承载力计算一、参数ωlim=ρte=(As+Ap)/Atedeq=∑nidi2/∑niνidiψ=1.1-0.65*ftk/(ρteσs)ωmax=αcrψσs(1.9cs+0.08*deq/ρte)/Es三、计算二、取值
本文标题:桩基抗拔裂缝计算
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