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B卷答案一、(满分5315分)1--5:FTTTT二、(满分20分)Solution:since134,,xxxareoptimalbasicvariables,wehave(最优基变量,我们有)1211140110,3,0,200100015BNBccb(4分)11011111001,101111211BBN(4分)1312TTBNcBNc(4分)150TBcBb(4分)Therefor(因此)(4分)三、(满分20分)Solution:Itsstandardformisas(它的标准形式)12312341235max234..232340,1,2,3iZSxxxstxxxxPxxxxxi(5分)12312341235max234..232340,1,2,3iZSxxxstxxxxxxxxxiandtheinitialsimplextableauis(和初始单纯形表)(5分)X1X2X3X4X5RHSX4-1-2-110-3X5-21-301-4Z234000ThenwehaveX1X2X3X4X5RHSX40-5/2-1/21-1/2-1X11-1/23/20-1/22Z04101-4(5分)andX1X2X3X4X5RHSX201-1/5-2/51/52/5X1107/5-1/5-2/511/5S009/58/51/5-28/5112280,**555TxSZ(5分)四、Solution:2004042,b=6,2024-6Ac(6points)1112232332323224200440426426426024-6-624246xxxfxAxbxxxxxxxxxx2200042024fxA(6points)Let0fx,i.e.1232324042602460xxxxx,wehave2*33x(6points)Since22000420024fxA,so*xisastrictlyglobalminimizer.(2points)五、Usethesteepestdescendmethodtosolvethefollowingproblem.(使用最速下降法来解决以下问题):221212min,32fxxxxBeginatthepoint111xandthetolerance(公差)0.(20points)Solution:since122322xfxxthenwehave1122dfxand1d,andmakealinearsearch(线性搜索)110minfxd(6points)Todothat,wedenote(为此,我们表示)221114,124221fxdfLet40200andweobtain10.5and(6points)21111430.5122xxd(3points)2200dfx,20dHence,theoptimalsolution(因此,最优解为)23*2xxand*0f(5points)
本文标题:桂林电子科技大学最优化方法B卷答案
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