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当前位置:首页 > 机械/制造/汽车 > 机械/模具设计 > 内齿棘轮月形棘爪型棘轮扳手的设计计算
,168,13,M=0.142L(kgm),110,M=1030.142L(kgm),::199811(050021)1.,,,,2.1311121314151617181911011,329,,,45,6,45,,,3.(1):;;()90;:m;Z;h;f0();hJ;fJ;df;Rf;De;Re;RJ;ZJ;RN;ZN;b;l;Zl;A;ZA;AF2(2):df=mZ(1)Rf=dfö2(2)h=f0m(3)0f0fJ(4)fJ=2Z4sin(135-180öZ)-Z2(5)022De=df+2h(6)Re=Deö2(7)RJ=mZJ(8)ZJ=2Zö4sin(135-180öZ)(9)hJ=RJ-Rf=fJm(10)RN=(RJ+Rf)ö2=m(ZJ+Zö2)ö2=mZN(11)ZN=RNöm=(ZJ+Zö2)ö2(12)ZA=Aöm(13)AF=45+90öZ(14)l=R2f+R2J-2RJRfcos(180öZ)=mZl(15)Zl=Z2ö4+Z2J-ZZJcos(180öZ)(16)4.3;O1;O2;A;BO2,O2A(R1)O1,(Re-D)(D7),AiiAZ5.O1F(O1,(RJ+Rf)ö2)RNF(3)FAN(4),O1,FJ;RN,4FQ;FJFQO2,FH:FH+FJ+FQ=0(17)FQLQ=FJLJ(18)121999338LJ=AsinAN(19)LQ=RN-AcosAN(20),FJFH(),CF,CF=arctgLJLQ=arctgAsinANRN-AcosAN=arctgZAsinANZN-ZAcosAN(21)FH=FJcosCF+FQsinCF(22)FJ=FQctgCF(23)6.(1)ZGZG,,,ZG,ZG=24(2)(22)(23),,mZ,FQFJFHCFCF=0,FH=FJ=;CF,FJFH;CF=90,FJ=0,FH,FH=FQCFA,,O2,S(4),H,AA=0.3df,ZA=0.3Z(3)F,CF=90,,CF90CF,CFCFmax=arcsinARN=arcsin2ZAZö2+ZJ(24)CF,FAN=90-CFmax(25)F,AN,AZ,AZ=AN-90öZ(26)AZ,360öZ7.,,HH3AO2BO1BO2O1AO2H=arccosA2+R21-R2f1AR1-arccosA2+R21-(RE-D)22AR1(27)R1=A2+R2f-2ARfcosA1(28)DO1O2,,D=(14)mm,8.,,(1):FQ=M0RN(29)M0kkFY,FYFQFJ,FY=FJsinAF+FQcosAF(30)(23)(29)FY=M0RN(ctgCFsinAF+cosAF)(31),kSb22lk:S=blk(32)RY:RY=FYSZGW=M0RNctgCFsinAF+cosAFblkZGW=M0bm2C(33)C=ctgCFsinAF+cosAFZNZ1KZGW(34)C(,)Zl(16)W,W=0.70.8,,k=f0fJ(k=0.950.99)(35)ZGkk,ZNkk(12)CFkk(24)AFkk(14)RY1K0Rb(36)Rb,k0,k0=1.32.5,(2)Z(Z,3600),C,m(m,0.05),(33)(36)mK0M0bRb(37)(3)FH,,:,,:11;21;31;41,;CCD,,(0101510-6L)()CADöCAMCADöCAMSUNI2DEASCADöCAM,5,,CADöCAM,,90,,,:()2000,,()CNC,,,90,,()321999338
本文标题:内齿棘轮月形棘爪型棘轮扳手的设计计算
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