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练习三学院班级姓名学号1.如图所示电路中,设开关动作前电路已经处于稳定状态。在0t=时开关S闭合,求()Cut。解:126)0()0(CCuuV;0)(CuV;7123210310100103CRsttCeu81033.0)(126V(该电路为零输入响应)2.图示电路中,R1=6kΩ,R2=1kΩ,R3=2kΩ,C=0.1μF,IS=6mA,换路前电路已经处于稳定状态,求S闭合后的()Cut和)(tCi。解:361)0()0(RIuuSCCV;833211)(RIRRRRuSCV;46332110914101.010]2//)16[(]//)[(CRRRsttCeu6430)(288V(该电路为全响应)ttCtCeedtduCi643064306)(018.0)6430(28101.0A3.如图所示电路为发电机的励磁电路,励磁绕组的参数为R=40Ω,1.5LH=,接在U=120V的直流电源上。当打开开关S时,要求绕组两端的电压不超过正常工作电压的2.5倍,并使电流在0.05s内衰减到初值的5%,试求并联放电电阻为多大?(图中二极管的作用是,当开关S闭合时,放电电阻dR中无电流,当S打开后,绕组电流将通过dR衰减到零,此时二极管如同短路。)解:340120)0(RUiLA;UiRLd5.2)0(;由此可知:100dR又:05.03dRRL;由此可得:50dR;故:10050dR4.图示电路中,开关S原与“1”接通,电路已达稳态。0t=时,S换接到“2”,试求电流i和电压)(tLu。已知10SUV=,R1=R2=R3=10Ω,L=1H。解:5.010101021)0()0(RRUiiSLLA;0)(LiA;2.010//101//32RRLs;ttLei5)(5.0A(该电路为零输入响应);ttLtLeedtdiLu55)(5.2)5(5.01V5.如图所示电路中,已知R1=10kΩ,R2=40kΩ,R3=10kΩ,US=250V,C=0.01μF。开关S原闭合,试求开关S断开后电压uab的变化规律。解:50211)0()0(SCCURRRuuV;250)(SCUuV;463321051001.010)1040()(CRRsttCeu2000)(200250V(该电路为全响应)tCCtabeudtduCRu20003)(160250V6.如图所示,R1=100Ω,R2=100Ω,R3=150Ω,L=0.1H,100SUV,C=2000μF,电路开关S不闭合时处于稳态。试问:⑴S在t=0时合到端子a,求uC(t)和iL(t)?⑵S在t=0时合到端子b,求uC(t)和iL(t)?解:⑴4.015010010032)0()0(RRUiiSLLA;40100150100100322)0()0(SCCURRRuuV;0)(LiA;0)(CuV;100012RLLs;2.010200010061CRCs;ttLei1000)(4.0A;ttCeu5)(40V;⑵4.015010010032)0()0(RRUiiSLLA;40100150100100322)0()0(SCCURRRuuV;11001002)(RUsiLA;100)(CuV;100012RLLs;2.010200010061CRCs;ttLei1000)(6.01A;ttCeu5)(60100V;
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