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2019125601={|1}Axx{|2}BxxAB=A(-1+)B(-2)C(-12)D2z=i(2+i)z=A1+2iB-1+2iC1-2iD-1-2i3a=(23)b=(32)|a-b|=A2B2C52D50453532A23B35C25D155ABCD6f(x)xf(x)=e1xx0f(x)=Ae1xBe1xCe1xDe1x7ABCD8x1=4x2=4f(x)=sinx(0)=A2B32C1D129y2=2pxp02213xyppp=A2B3C4D810y=2sinx+cosx(-1)A10xyB2210xyC2210xyD10xy11a022sin2=cos2+1sin=A15B55C33D25512FC22221xyaba0b0OOFx2+y2=a2PQ|PQ|=|OF|CA2B3C2D5452013xy23603020xyxyyz=3xy___________.14100.97200.98100.99___________.15ABCABCabcbsinA+acosB=0B=___________.161.2481_________________237017212223601712ABCDA1B1C1D1ABCDEAA1BEEC11BEEB1C12AE=A1EAB=311EBBCC1812{}na1322,216aaa.1{}na22lognnba{}nbn1912100yy[0.20,0)[0,0.20)[0.20,0.40)[0.40,0.60)[0.60,0.80)22453147140%20.01748.602.201212,FF2222:1(0)xyCababPCO12POFC2P12PFPF12FPF16ba2112()(1)ln1fxxxx1()fx2()=0fx10222322[4-4]10O000(,)(0)M:4sinCl(4,0)AOMP.10=30l2MCPOMP.23[4-5]10()|||2|().fxxaxxxa11a()0fx2(,1)x()0fxa.20191C2D3A4B5A6D7B8A9D10C11B12A139140.981534162621171B1C1ABB1A1BEABB1A111BCBE1BEECBE11EBC21BEB1=90.RtABERtA1B1E1145AEBAEBAE=AB=3126AAAE.1EFBBFEF11BBCC3EFAB11EBBCC1363183V181naq22416qq2280qq2qq=4na121242nnna212(21)log221nbnnnbn21321nn19110040%1470.2110020.0210040%21%2%21(0.1020.10240.30530.50140.707)0.30100y52211100iiisnyy222221(0.40)2(0.20)240530.20140.407100=0.02960.02960.02740.17s30%17%2011PF2POF12FPF1290FPF2PFc13PFc122(31)aPFPFcC31cea.2(,)Pxy1||2162yc1yyxcxc22221xyab||16cy222xyc22221xyab222abc422byc22216yc4b22222axcbc22cb2222232,abcb42a.4b42aP4ba[42,)211()fx0+.11()ln1lnxfxxxxx.lnyx1yx()fx(1)10f1ln41(2)ln2022f0(1,2)x00fx.0xx()0fx()fx0xx()0fx()fx.()fx.210(1)2fxf22ee30f()0fx0,xx.01x011x.1111()1ln10ff1()0fx00,x.()0fx22100,MC0304sin233.||||cos23OPOA.(,)QlP.RtOPQcos||23OP(2,)3Pcos23lcos232(,)PRtOAP||||cos4cos,OPOA4cosPOMAPOM,42.P4cos,,42.231a=1()=|1|+|2|(1)fxxxxx.1x2()2(1)0fxx1x()0fx.()0fx(,1).2()=0fa1a.1a(,1)x()=()+(2)()=2()(1)0fxaxxxxaaxx.a[1,)
本文标题:2019年全国II卷文科数学高考真题
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