分析化学有关计算公式

TxEa−=%100%100E_r×=×−=TETTxaxxdii−=nxxdi∑−=%10021×+++=nddddiLLµ=∞→xnlim()∑−=nxi/2µσ2.()()∑−−=1/2nxxsi3.4.0000001000×=xSCV()∞→=nnxσσnssx=σµ−=xu2221)(ueuy−=Φ=πσσµ−=xunuxuxxσσµ±=±=xuuσσnstxstxfpxfp,,±=±=µ⎯12111nnnnxxxxQQxxxx−−−==−−1Q1x1,x2,……,xn2xnx13xnxn-1x2x14QQ2(Grubbs)1x1,x2,x3,x4……2s3GSxxGSxxGn1−=−=4G5GG(Grubbs)Q--------1.(µ)-tx/tSnµ−=2.22SSF=2)1()1(21222211−+−+−=nnSnSnS121212||nnxxtSnn−=+ff1f2n1n21.(HA-A)KaKb1400abwppp.KKK+==2.γa=c⎟⎟⎠⎞⎜⎜⎝⎛−+−=γI30.0I1IZ50.0lg2ii∑==n1i2iiZc21I:=1:=1:=1aγγ3.:i=[i]/c]H[KKaaA++=δ−2a1a1a222222AHKK]H[K]H[]H[]A[]HA[]AH[]AH[C]AH[2++=++==δ+++−−2a1a1a21a22HAKK]H[K]H[K]H[]A[]HA[]AH[]HA[C]HA[++=++==δ+++−−−−−2a1a1a22a1a2222AKK]H[K]H[KK]A[]HA[]AH[]A[C]A[2++=++==δ++−−−−−4.H+[]2K4ccHW2++=+c10-6mol/L[H+][Cl-]pH=-lgc(c)2c/Ka400cKa20Kw(b)1c/Ka400cKa20Kw(a)c/Ka400cKa20KwacK=+]H[WaKcK+=+]H[[]2CK4KKHa2aa++−=+400,20,401121awaaaKcKcKKcK400,20,401121awaaaKcKcKKcK[]2CK4KKH111a2aa++−=+(a)(b)1]H[acK=+Ka2c20Kwc20Ka121]H[aaKK=+cKKcKKHawaa++=+121)(][12Ka2c20Kwc20Ka1cKcKK]H[121aaa+=+3Ka2c20Kwc20Ka1c)KcK(K]H[waa21+=+HAAaccpKpH−+=lgdpHdadpHdb−==β)1(c3.2c3.2HAHAAHAδ−δ=δδ=β−2aa])H[K(]H[Kc3.2+++=−+=AHAcccββpH=pKa1b=1/3bmaxpHpH=pKHInpH=pKHIn1(2pH)cspKa10-8:b:HAa:%100][][,,×⎟⎟⎠⎞⎜⎜⎝⎛−−=+−epHAcepHAcepeptcHOHEδEt=[OH-]ep-[H+]epcHClep100%nnLMMLK]][[][=KMLLMKnn1][]][[==nKKKKKKnLL2121121⋅=⋅==βββ[ML]=1[M][L][ML2]=2[M][L]2[ML3]=3[M][L]3……[MLn]=n[M][L]n1]][[][K,][]][[1526H62651aaKHYHYHYHHYHK===++++++HnH2H1H2H1H1H1KKKKKkLL=β=β=βHnH2,,,6655144332210][][][][][][][11++++++++++++++=HHHHHHHHHHHHHHβββββββδMcMLCLcM=[M]+[ML]+[ML2]+……+[MLn]cM=[M]1+1[L]+2[L]2+……+n[L]nnn221MM0]L[]L[]L[11c]M[β++β+β+==δ=δL]L[]L[]L[]L[1]L[c]ML[10nn2211MML1βδ=β++β+β+β==δ=δLnn0nn2211MnMLn]L[]L[]L[]L[1]L[c]ML[nβδ=β++β+β+β==δ=δLYY:]N[K1]Y[]NY[]Y[]Y[]Y[NY)N(Y+=+=′=α6H62H1H1)H(Y]H[]H[]H[1+++β++β+β+=αL)H(Y)N(Y)H(Y)N(YY1α+α≈−α+α=αMnn22n2)L(M]L[]L[]L[11]M[]ML[]ML[]ML[]M[]M[]M[β++β+β+=++++=′=αLLnn221n2)OH(M]OH[]OH[]OH[1]M[])OH(M[])OH(M[)]OH(M[]M[]M[]M[−−−β++β+β+=++++=′=αLL)OH(Y)L(M)OH(M)L(MM1α+α≈−α+α=α]][[][YMMYKMY′′=′[Y]]Y[,[M]]M[YMα=′α=′YMMYMYKKα−α−=′lglglglgYMYMYKKα−=′lglglgMMYMYKKα−=′lglglg)lg(21,MYspMspKpcMp′+=′pMeppMsppM[MIn]=[In]lgKMIn=pM=pMt=pMep%100Kc1010EMYsp,MMpMpt×′−=′∆−′∆cM,spKMY106lgcM,spKMY6lgYHlgKMY–8pHlgK+lgC6CN=CMlgK6oxRedRedoxOox/Red'Oox/Redαγαγlgn0.059EE+=cclgn0.059Ecαγcαγlgn0.059EERedox'Oox/RedRedoxRedoxRedoxOox/Redox/Red+=+=KccccEEnba′==−lg)()lg(059.0)(Red2Ox2Ox1Red1'O2'O121O22O11spnnEnEnE++=′′2θ'2n30.059E×+E1θ'1n30.059E×−T=It/I0AlgI0/It)=KbcAlgTS=M/cbbcbcAAAbcAbcAsxsxssxx∆κ=κ−κ=−=∆κ=κ=A1=a1bcab1bcbA2=a2bcab2bcbαnnnnnncAAAnAAAKAAAnccRMMRK1)''()''(1'/)'())((1]][[][+−−−=−=−==ααααnnnnnMRncfMRfcMRRMMRK]}[)1]){([(][]][[][n−−−==BAAAQQAAR)(==ABABBAABRRQQQQS=×=00/)()(SB/A[A][A]=DKWOCCD=%100V/VDD%100VCVCVCEO×+=×+=()[]nwOwOnVDVVmm+⋅=/00mmmEn−=%100×=HClHClNaOHNaOHVcVc−=laRaf=,amKd=:():()mkgdmm