您好,欢迎访问三七文档
当前位置:首页 > 商业/管理/HR > 商业计划书 > 两招搞定简单多面体外接球问题
■..、..1n.2n、.3n、..111.A-BCD2ABD⊥BCDBDO1AO1CO1△ABD4△BCD2BC=CD=槡22∠BCD=90°AO1⊥BCDOAO1BO.RRt△BOO1BO2=OO21+BO21R2=22+槡23-R2R=槡433S=4πR2=64π3...22009ABC-A1B1C1AB=AA1=4AC=槡3∠BAC=30°.33ABCA1B1C1O1、O2O1O2OAO1AO1O2OOABC-A1B1C1.OBC2=AB2+AC2-2AB·AC·cos∠BAC=7BC=槡7△ABCr2r=槡7sin∠BAC=槡2213r=槡213.Rt△AOO1R=AO=AO21+OO槡21=13槡3.S=4πR2=4π·133=52π3..、..1、、.2.3、.4544·81·4AC2+AD2+CD2=2AB2..32012P-ABCP、A、B、C槡3.PA、PB、PCABC.PA、PB、PCP-ABCPA、PB、PC5O.R2R=槡23R=槡3ABCOABCd=R-2R3=R3=槡33.55100■..y=4-sinx3-cosx.1y=4-sinx3-cosxsinx-ycosx=4-3ysinx-φ=4-3y1+y槡2|4-3y1+y槡2|≤1.6-槡64≤y≤6+槡64y6+槡64..2y=4-sinx3-cosx.p34cosxsinxcosxsinx.P34y-4=kx-3kx-y+4-3k=0.111|4-3k|=1+k槡2k=6±槡64.y6+槡64.sin2θ+cos2θ=1.3y=4-sinx3-cosxk=4-sinθ3-cosθx=cosθy=sin{θk=4-y3-xkx-y+4-3k=0.Mxykx-y+4-3k=0x2+y2=1d≤r|4-3k|1+k槡2≤1.6-槡64≤k≤6+槡64y6+槡64.d≤r.4、y=4-sinx3-cosxk=4-sinθ3-cosθx=cosθy=sin{θk=4-y3-xkx-y+4-3k=0.Mxykx-y+4-3k=0x2+y2=1.x2+y2=1kx-y+4-3k={01+k2x2+2k4-3kx+9k2-24k+15=0Δ≥06-槡64≤k≤6+槡64y6+槡64.、·91·
本文标题:两招搞定简单多面体外接球问题
链接地址:https://www.777doc.com/doc-5873512 .html