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差分放大电路例题例1:β=100,rbb‘=100,静态时vo=0V(1)计算静态电流(2)计算差模放大倍数例题1静态分析mAIIImARVImA.RVImA.RVVVVIII,iVvECCeBEEeBEECEEBEBECCRCCC121274630032134366443465OO====≈≈≈≈====≈≈≈≈====≈≈≈≈====≈≈≈≈++++−−−−−−−−================所以即例题1动态分析939815386//217.212610110065.065.07.42610110021521211525=×=−≈−=−≈−=≈×+===≈×+=vvdvbeLvbeiCvdbebeibeAAArRArRRAKmAmVrKrRKmAmVrββ例2222:电路如图,静态时,Vo=0Vo=0Vo=0Vo=0。求R=R=R=R=?T5T6T3T4R83.6KR95.1KR310KR410KR51.8KR21MR66KR76KRvi+15V-12VT1T2R11Mvo解:(1)(1)(1)(1)静态分析:IC3=IC4=2mAVR5=2IC4R5=7.2VVR3=VR4=VR5+VBE3=7.9V例2静态分析ID1=ID2=0.79mAVR8=VR9=2ID2R8=5.7VVR=12-0.7-VR8=5.6VIR9=VR8/R9=1.1mAR=VR=VR=VR=VRRRR/I/I/I/IR9R9R9R9=5.1K=5.1K=5.1K=5.1KT5T6T3T4R83.6KR95.1KR310KR410KR51.8KR21MR66KR76KRvi+15V-12VT1T2R11Mvo例2动态分析设β=150,gm=3mA/V,rbe3=rbe4=2.16k20821472≈=beVrRAββββKrRbeid16.232==3.5'1≈−=LmVRgA110821=×=VVVAAA输入输出同相T5T6T3T4R83.6KR95.1KR310KR410KR51.8KR21MR66KR76KRvi+15V-12VT1T2R11Mvo
本文标题:差分放大电路例题答案
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