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24⎟⎠⎞⎜⎝⎛⎟⎠⎞⎜⎝⎛⎟⎠⎞⎜⎝⎛29sin,1516cos,23sintttπππ58,815,34321===TTT1740πf4(t)1740π7⎥⎦⎤⎢⎣⎡+=)(78cos)7/8cos(NkkππnNππ278=)4(747===nnN⎥⎦⎤⎢⎣⎡−)12(tfdtd)1()()()()1()(−−=∇−+=∆kxkxkxkxkxkx∑−∞==knkxkx)()(118)3()5332()3(|)52(5523552=−−+×=−−+=∫∫−=−dttdtttttδδ0=[]41)2()2(41)4(1001002=++−=−=∫∫dtttdttδδδ)(2)(2)(2)1()2()1(22tdttdttttdtttttttεδδδ==++=++=∫∫∫∞−∞−∞−)(21)()()()()()(tutuCtititititicRcs+′+=++=)()(tutuC=)()()(3)()()()(0)()()(3tiLtiLtitutitititutiLtissLL′+′−=⇒⎩⎨⎧−==+′+−)(2)()(2)(5)(7)(2)(21)(21)(23])()()(3[)()(titititititititititititititissssss+′+′′=+′+′′⇒′+′−+′′+′−+=)(21)()(31)(tutuCtuticRs+′+=)()(21)()()(21)()(0)()()(tutututututuCtitutiLtuRCLLR+′+′′=⇒⎪⎩⎪⎨⎧+′==+′+−)(6)(5)(7)(2)(21)()(31)(61)(31)(titututututututututiss=+′+′′⇒+′++′+′′=αβαβαβαβα)()()()()()()()()(2tiLtuRtututititituCtiLcLcC′=−−=−=′=⎪⎩⎪⎨⎧−=−=12)()()()()()(RtutftiRtitutuCLC⎪⎪⎩⎪⎪⎨⎧−=−−=LtiRtutiCtiCRtuCRtftuLCLLCC)()()()()()()(211&&⎪⎩⎪⎨⎧′′=′′′=′−′−=′′)()()()()(2)(3)()(tytxtytxtytxtftx)()(2)(3)(tftytyty=+′+′′····εε→∞→∞ε→∞→∞≥≥≥≥x≥ε≥εεf≥εf≥1222)()()(,000//|==−==∴→→∫∫∞∞−−∞∞−ττδτττKeKdteKdttfttfttQτ2/1=⇒KttKdeKtftjτωττω/sin2)(/1/1∫−==12)/(//sin2/sin2)()()(,0=−===∴→→∫∫∫∞∞−∞∞−∞∞−πττττδτKtdttKdtttKdttfttfQπ2/1=⇒K5/2/2,5)5sin5(cos)(5πωπω===+==TtjtAAetftjπωπω===+==−+−/2,2)2sin2(cos)()21(TtjtAeAetfttj0)(*)(,021=tftft)()()(*)(,020220)(2021|teeeededeetftftttttttttεττττττ−−−+−−−−−====≥∫∫0)(*)(,021=tftft)()cossin(212)cos(sinsinsin)(*)(,0|00)(021ttteeedeedetftfttttttttετττττττττ−+=−===≥−−−−−∫∫0)(*)(,221=−tftft)2()()2()()(*)(,2133233313)(331221|+−=+−===−≥+−+−+−+−−−+−∫teeteeeeedeetftftttttttttεεττττ∑∞−∞=−=nTnTttttf)()()(δδ[][])(*)()()()(*)()()(21tgttftftgttftfTTττδδ==∴[][])2()1()1()1()13()1()12()1()1()1(*)3()2()1(*)3()2()(*)()(*)()()2()1()13()12()1()1()1(2121−−−−−=+−−−+−−=+−−−−=+−−−=′==−−−−+−−+−−+−∞−+−−∫tetetetetettdttetttftftftftytttttttεεεεεδδεδδ)()()()(11)(tftftytypppH+′=+′⇒++=)(3)()(2)(3)(233)2)(1()3()(22tftftytytypppppppppH′+′′=+′+′′⇒+++=+++=⎪⎩⎪⎨⎧=−++−=+++−−=−−)()()()1()(0)()/11()()(0)()()(3321321321tftitiptpitipptitpitpitpitpi)322()()12()()322(/)12(11/111311)(/1113)()322()()332()()322(/)332(11/11131)(/11003)()322()()12()()322(/)12(11/111311)(/11100)(232232323223222322321+++++=+++−++−=−+−++−−−−−+++−−−−=+++++=+++−++−=−+−++−−−−−−++−−=+++++=+++−++−=−+−++−−−−−+++−−−=pppptfppptfpppppppppppppppptfpppppptipppptfppptfppppppppppppppptfpppppptipppptfppptfpppppppppppppppptfppppti1)(0y)(0y2)(p44ppA(p)xx22==+=++=−+Qt)ec(c)(y-2t1110x+=∴tt)e2c-cc2()(y-2t111110x+−=′t⇒⎩⎨⎧==⎩⎨⎧=+−=3c1c1cc21c11101110100tt)e3(1)(y-2tx≥+=t)(0y)(0y2i)22i)(p2(p)84pp(A(p)(i)x(i)x2−+=−+++=++=ppQececc)(y2i)t-(2302i)t-(22010x−+++=∴te2i)c-(2ec)22()(y2i)t-(2302i)t-(220x−+−+−=′itec2i)-(2ec)22()(y2i)t-(23022i)t-(2202x−+++=′′it⇒⎪⎩⎪⎨⎧−=−==⎪⎩⎪⎨⎧=−++=−−+−=++4/1c4/1c2/1c0c2i)2(c2i)2(12i)c2(2i)c2(0c3020103022023020302010cc0cos2tte2121)ee(e4121)(y2t-2it2it2t-x≥−=+−=∴−t2132265pp5p-p3p(p)223++++−=++−+=pppH)(e)(e2)(2)()h(-2tt3-tttttεεδδ++−′=∴ipippiiH322/1321/22)32p)(32p(p2610pp3)314pp(p2610pp3(p)222−+++++=−+++++=++++=)(cos3t)e2()h(-2tttε+=∴211223pp3p(p)2+−+=+++=ppH2))(p1(pA(p)++=ecec)(y-2t20-t10x+=∴te2cec)(y-2t20-t10x−−=′t⇒⎩⎨⎧−==⎩⎨⎧=−−=+3c4c2c2c1c201020102010c0t3ee4)(y-2t-tx≥−=∴t(t))e2e()h(-2t-tε−=t(t))0.5ee2-(1.5(t))e-(121-(t))e-2(1(t))ee2(*)()(*)()(y2t-t-2t-t-2t-t-fεεεεε+==−==tthtft(t))2.5ee2(1.5)(y)(yy(t)-2t-tfxε−+==+=tt[](t))ee((t))e-(e)e-(e(t))ee2(*)(e)(*)()(y-2t-t-3t-2t-3t-t-2t-t-3tfεεεε−=−=−==tthtft(t))4ee5()(y)(yy(t)-2t-tfxε−==+=tt42204,04/)2(14/0)(*)()(y22f≤≤⎪⎩⎪⎨⎧−−==ttttttthtftA)(1)i(0V)(1)0(-u)i(0R--c-−=∴−==⋅(t)e)(i10,(t)e)(i0)i(t)1(p01/p)i(t)(1t-x1-t1xεε−=∴−==⇒=+⇒=+tcctfε(t)e10(t))e-10(1-(t)10(t)10*(t)]e)([(t)f*(t))(y(t)e)()(h1111/111(p)(t)f1/p)i(t)(1t-t-t-11ft-1111εεεεεδεδ==−==∴−=⇒++=+=+=⇒=+thtttppppHfε(t))e--(1(t)*(t)e(t)f*(t))(y(t)e)(h11(p)(t)p)(11i(t)(t)p)i(t)(1(t)),i(i(t)p1-Ri(t)t-t-22ft-22s2εεεε=−==∴−=⇒+−=⇒+−=⇒−=++=⋅httpHiiss(t))1(10e)(y(t)y)((t))11e--(1)(y)(y(t)yt-xf-tfff21εε−=+=⇒=+=∴ttytt)1(p)1p2p(A(p)22+=++=Qt)ecc()(y-t1110x+=∴tect)ecc()(yt11-t1110x−++−=′t⇒⎩⎨⎧==⎩⎨⎧=+=3c1c2cc-1c11101110100te)31()(y-tx≥+=∴tt()111K1K12pp1p(p)2212+=+++=+++=pppH(t)e)h(-tε=t(t))e-(e(t)e*)(e)(*)()(y-2t-t-2t-tfεεε===tthtft(t)e(t)e)3(2)(y)(yy(t)-2t-tfxεε−+=+=ttt(t)e)(-2tε=tfQ1Q)(2)(44)(4)(y)(2)(y)()(y022200020p20p20p⇒⎯⎯⎯⎯→⎯⎪⎪⎩⎪⎪⎨⎧=′′−=′=∴−−−−−−teeteQQQteQtteQtteQtttttttεεεεε0te)(y-2tp≥−=∴t(t)e)3(2)(yy(t))(y-tphεttt+=−=)()(ff(t)21tft+=)(2)(f)(1)(f21⎩⎨⎧=−=ttttεε(p)21211/2(p)12(p))(u)(uu(p)21fppppfpfpp⎟⎟⎠⎞⎜⎜⎝⎛+−+=+−+=−=ppppppp++−+=++−+=⎟⎟⎠⎞⎜⎜⎝⎛+−+=2212/12/12211212121H(p)(t)2ee21)()(2t-t21-εδ⎟⎟⎠⎞⎜⎜⎝⎛++−=tth(t))e(e(t)]1[*)](e2)(e21)([)(*)()(y2t-2t-2t-2t-1xεεεεδ+=−++−==tttthtft(t))e-e-(12(t)*)](e2)(e21)([2)(*)()(y2t-2t-2t-2t-2fεεεεδ=++−==tttthtft(t))e-e-2()(y)(y)y(2t-2t-fxε=+=∴ttt[]0sinsin1coscoscos)(020220∫∫∫=−=−=πππππππntntnntdtntdtntdttffntπ⎩⎨⎧−=2/~000~2/)(TTAtfAdtATdttfTaTT===∫∫−02/002)(20sin2cos2cos)(202/02/0=ΩΩ=Ω=Ω=−−∫∫TTTnntnTAdttnTAtdtntfTa[]⎩⎨⎧==−=−=ΩΩ−=Ω=Ω=−−∫∫,..6,4,20,...5,3,1/21coscos2sin2sin)(202/02/0nnnAnnAntnTAdttnTAtdtntfTbTTTnπππ∑∑∞=∞=Ω−−−=−Ω−Ω−Ω−=Ω+=11)12sin()12(22...5sin523sin32sin22sin2)(nnntnnAAtAtAtAAtnbAtfπ
本文标题:信号与系统课后习题答案(西安电子科技大学)
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