模拟电子电路 练习卷 4

5.7晶体管abcdeVBE(mV)690690580780820IC(mA)1.0001.0000.13010.1073.95IB(μA)507071201050IE(mA)1.0501.0700.13710.2275.00α0.9520.9350.9490.9880.986β2014.2918.5784.1770.43IS(A)1.03e-151.03e-1510.922e-15284.66e-184.208e-165.20110.70.7()110aImA2410()2.52.4125.62.52CbImAkVV5.2043()0,1V0(10)1100,1mABCBcIVImAkII又6100.7(10)()0.9651550,10150.9654.475CBCEdImAkkIIIVkV5.40/(1)2.4114/,341.812/1.81.71(2/34)200.3,1.722220,621.8VCEBETvCSAAAACoCCECCECCEviIeVVVVVImAVArkIvVimAvimAkvV则接近饱和区时，则时，5.56330.3,0.3,(5)|510|0.355100.3,156.67,157.67/,0.005783.351.083CCCCCEVTTCEOCEvbeCCVVTvvvvceCEceCEIRVVAVVVvvVAvvIRAAVAAAVVvAmVvvVV输出波形接近饱和区，但不进入饱和区，5.8411111122222()0,10,20.7100.71.023100.740.70.71.4,41025100.2BECECCECECCaIVVVImAIRVIRVVVVImAIRVIRV，假设两管工作在放大区假设成立。5.841111111112122212()1001210.0091,10.91,0.91,(1)0.922101.6282()0.7(1)0.017310()BBBCBEBEECBCBEBCBCbQQQImAVIRVIImAIImAVIRVQIIRIRImAVIIRB1E1B1B，假设，工作在放大区对于有：10-(1+)IR-0.7-IR=0对于：12222221.87230.311.7,(1)1.72410222.56,5101.27540.32CBEBCCVVVVQIImAIImAVIEREVVIRVVVVQ工作在放大区又工作在放大区5.9011,0,13,3391,10.1,12/3020.73.712117.67,212.33118,213,1BCERCCERECCCCECECERCCRBCCREBBCEIIIVVVVVImAVVRkRkIIIIERRVIkRVVVVRRRkRkVRkRkRRk(1)首先假设则又取则又选择合适电阻且稍大于理想值，则5.90E90,23.77,1||27.55120.72.83,2.8/(1)9103.09,3.052.812,0.73.5125.95118,213,1BBCCBBBECEEBECEBECCCCCCRVVVRRRkRRVImAIImARRRImAImAVVVVVVVIRVRkRkR(2)则电阻为以上取值可见略小于设计要求，因此减小则910EkR，5.11210.55*7.51.25/20//*7.5150/CECCmCTvcimIImAVIkVgIVmAVAvvgkVV很大，5.130212121593.212715//15//279.643.210.7/(1)1.29.64/1011.940.991.9476.8/0.0251001.3,76.810052.10.991.94BBCCBBBBEEEBCmTmAoCRVVvRRRRRkVVIRRmAIgmAvVrkgVrkI5.130si//9.64//1.31.15//2.11(////)1.1576.8(2.11//2)8.13/101.15//()101.158.13()45.2inBoutCOoiOinmooLvsigiSigingooLosiginiisigsiginsigLRRrkRRrkvvvRgvrRRGvvvRRvVVivRvRRAivRRvR3/AAvibce300k250re30kieieVo5.137EBC(a)I=I+I=0.5mA0.99*0.50.4952.28CECEEBEBBIImAVIRVIRV注意到()500(1)30030(2)250300/90/TeEoioeiieeoiVbrIcKCLvvvikkvvirvvVV在点根据列电流关系方程，即5.144(1)2.525TTBEVVkIIEBEBE根据直流通路，可得5-I*3.3k-0.7-I*100k=0又I=(1+)II=1mAr5.144vsig100kviRinribibRout1kvobec3.3k(1)(3.3||1)(1)(3.3||1)80.04(1)(3.3||1)0.968/(1)(3.3||1)0.43//77.48//1003.3||ibbinbboioioinosigsigiinsigiooinLiiniLoutvirikkRiirkkkvkkVVvrkkvvvRvVVvvvRRvivRvoRAAiviRvRrRk776.31k5.149010020/5100xCmTmAoCrIgmAVVrkgVrkI00015.67(1/)0.620.644.852()mCBCdeFmjedejedemTCCfFVVCgpFCCCCCpFgfGHzCC5.15320/2()0.547.533.3CmmTTTmIggmAVfVCCCpFfrkfMHzg且5.15901212/10||||()5.7(||||)16.11/CEmTTminxoioMsigsigiinmoCLinsigxIIgmAVVVrkgRRRrrkvvvvAvvvvRrgrRRRRrrVV12||[(||||)]2.69||||2.532.73121.73(1)3311.792sigxsigLoCLmTinmLHinsigRrrRRRkRrRRkgCCpFCpFfCpFCCgRCpFfMHzCR又