大学数学概率论及试验统计》第三章课后答案(余家林主编)

    课后答案网，用心为你服务！  大学答案---中学答案---考研答案---考试答案 最全最多的课后习题参考答案，尽在课后答案网（）！Khdaw团队一直秉承用心为大家服务的宗旨，以关注学生的学习生活为出发点，旨在为广大学生朋友的自主学习提供一个分享和交流的平台。 爱校园（）课后答案网（）淘答案（） 493-11XY1=X2Y2=2)2(-X.X1234P0.10.20.30.4x1234p0.10.20.30.4x-2-1012(x-2)21014x-2:x-2-1012p0.10.20.30.4(x-2)2:(x-2)2014p0.20.40.423122XYYXZYXZ-=+=21x,yX+Y2334p01/31/31/3XYX-Y-101p1/31/31/3X+Y234p02/31/33XYP{X=k}=kaP{X=k}=2kb,k=1,2X+Yab,2aa+=1,a=32,b+4b=1,b=54:XY1218/152/1524/151/15YX12101/321/31/350X+Y234p8/156/151/15(,)4XYXYX131415P0.30.60.11225324:X,Y:XY101112130.060.210.03140.120.420.06150.020.070.01X+Y2324252627P0.060.330.470.130.01(2)25,{X+Y25}={X+Y=26}{X+Y27},P{}25+YX=0.13+0.01=0.14(3)24P{X+Y24}=0.065XYP{X=1}=P{X=2}=0.5,P{Y=1}=P{Y=2}=0.5,Z1=X+YZ1=2XZ1Z2:(X,Y):YX12PX10.250.250.520.250.250.5PY0.50.5Z1=X+YZ1=2XZ1Z2,,:Z1=X+Y,Z2=X+X,Z1XY.Z2X6XYZ1=Max{X,Y}Z2=Min{X,Y}YX12101/3Y101112P0.20.70.1Z1=X+Y234P0.250.50.25Z2=X+X24P0.50.55121/31/3:(X,Y)(1,1)(1,2)(2,1)(2,2)p01/31/31/3max{X,Y}1222min{X,Y}1112:max{X,Y}12P017X,Y,Z1=Max{X,Y}Z2=Min{X,Y}YX1211/92/922/94/9681X2X{})3,2,1,2,1(,31====kikXPiY1=Max{X1,X2},Y2=Min{X1,X2},Y1Y2:X2X11231X11/91/91/91/321/91/91/91/331/91/91/91/3X21/31/31/3P{Y1=2,Y2=3}=0,P{Y1=2}=93,P{Y2=3}=91P{Y1=2,Y2=3}P{Y1=2}·P{Y2=3}Y1,Y2.min{X,Y}12P2/31/3min{X,Y}12P5/94/9max{X,Y}12P1/98/9Y1123P1/91/35/9Y2123P5/91/31/9551XY=2XZ=2X::FY(y)={}{}∫⎪⎪⎪⎩⎪⎪⎪⎨⎧∫≤==⎭⎬⎫⎩⎨⎧==∞-22012,1120,202,0)(22yyyyxdxydxxpyXpyXpyYp∴YP(y)=⎪⎩⎪⎨⎧,020,2yy{}{}⎩⎨⎧∫===-zzZzdxxpzzxpzZpzF0,)(0,0)(2z0ZFz=∫∫∫∫⎪⎩⎪⎨⎧∫==+=--zzzzzzzzxdxdxxpdxxpdxxpdxxp00001,11,2)()()()(⎪⎩⎪⎨⎧≤≤=1,110,0,0)(zzzzzFZ⎩⎨⎧∈==,0)1,0(,1)()('xzFzPZz2Xpxa≠0Y=aX+bX~p(x),Y=ax+b)(yFY)(yFY=p{}yY={}{}⎪⎪⎩⎪⎪⎨⎧⎭⎬⎫⎩⎨⎧-⎭⎬⎫⎩⎨⎧-=-=+0,0,aabyxpaabyxpbyaxpybaxp=⎪⎩⎪⎨⎧-=⎪⎪⎩⎪⎪⎨⎧⎭⎬⎫⎩⎨⎧-≤-⎭⎬⎫⎩⎨⎧-∫∫-∞--∞-abyabyadxxpadxxpaabyxpaabyxp0,)(10,)(0,10,Y=ax+bPY(y)=⎪⎩⎪⎨⎧⋅--⋅-=0,1)(0,1)()('aaabypaaabypyFYaabyPyPY1)()(⋅-=31X~N012X~N2,smY=Xe56X~N),(2smY=xe{}{}⎪⎩⎪⎨⎧∫⋅≤===∞---ydxxxYyeyyePyYPyFln2)(0,210,0)(22smspY⎪⎩⎪⎨⎧⋅≤==--0,210,0)()(222)(ln'yeyyyFyPyYYsmsp4XU13Y=2XX~)3,1(UP(x)=⎪⎩⎪⎨⎧∉∈)3,1(,0)3,1(,21xxY=X2)(yFY{}{}yXPyYPyFY==2)(=⎪⎩⎪⎨⎧∫≤-yyydxxpy)0(,)(0,0∫-yydxxp)(=⎪⎩⎪⎨⎧∫∫∫=++∫∫≤+--1313113,1)()()(31,)()(yyyyydxxpdxxpdxxpydxxpdxxp⎪⎩⎪⎨⎧≤==,091,41)()('yyyFyPYY5XYN01Z=X+Y∫∫+∞∞-+∞∞--=-=dyyyzPdxxzxPzPZ),(),()(Z=X+Y=)(zPZ∫⋅∞+∞--+-dxexzx2)(2221pX,Y22221yxe+-⋅p=∫⋅⋅=∫⋅⋅=⋅∞+∞--∞+∞-------4)2(4222222222222212121zzxzzzxxzedxeeedxeepppX+Y~N(0.2)576521,......,,XXXN125P⎭⎬⎫⎩⎨⎧∑=5165iiX:521,......,,XXX∑=512)5,60(~iiNx⎪⎭⎪⎬⎫⎪⎩⎪⎨⎧-≤∑--=⎭⎬⎫⎩⎨⎧∑≤-=⎭⎬⎫⎩⎨⎧∑===56065560165165515151iiiiiixPxPxP=1-0.8413=0.15877XYN01Z=22YX+:X,YN(0,1)(X,Y)22221yxe+-⋅p22YXZ+=)(zFz{}{}{}⎩⎨⎧+≤=+==0,0,0)(22222zzYXPzzYXPzZPzFzP{X2+Y2z2},z0=∫∫⋅++-22222221zyxyxdxdyep1-22ze-⎪⎩⎪⎨⎧≤=-0,00,)(22zzzezPzZ8XYpxyX-YZ=X-YFZ(z)FZ(z)=P(Zz)=P(XYz)=òò+¥¥-+¥-zxdyyxPdx),(=òò+¥-+¥¥-zxdydxyxP)),((∫+∞∞--==dxzxxPzFzPZZ),()()('9XYp(x,y)=⎩⎨⎧+-,0;0,0,)(yxeyxZ=)(21YX+Z=(X+Y)/2FZ(z)=P(Zz)P{(X+Y)/2z}=ïîïíì×£òò---xzyxzzdyeedxz20200,0,0zxy-=y=-x+2z2z2z58=ïîïíì-£ò--zzxxzdxeex2020,)1(0,0⎩⎨⎧≤=-0,00,4)(2zzzezPzz10Rij(i,j=1,2)hlR11R12R1R21R22R2R1R2RRZZRij(i,j=1,2)Xij(i,j=1,2).R1,R2Z1,Z2,Z1=min{X11,X12},1Z)(1zFZ=2))(1(1))(1())(1(1111211zFzFzFXXX--=-⋅--,=[]⎪⎩⎪⎨⎧⎩⎨⎧≤-=≤-----0,00,10,00,)1(1122zzezzezzll))()(1211zFzFxX=2Z1Z.{}21,maxzzz=Z)()()()(2121zFzFzFzFzZZz=⋅=Z⎩⎨⎧≤⋅-=⋅==--0,00,2)1(2)()(2))(()(22''211zzeezFzFzFzPzzZZzzlll=⎩⎨⎧≤---0,00),(442zzeezzlll11XYU01min(X,Y)max(X,Y)Z1=min(X,Y),2))(1(1)(1zFzFxz--=XY,Z1Z1(z)=2(1FX(z))X(z),⎪⎩⎪⎨⎧≤≤=1,110,0,0)(zzzzzFX⎩⎨⎧∉∈-=)1,0(,0)1.0(),1(2)(1zzzzPZZ2=max(X,Y),)(2zFZ,)()(22zFzFXZ=2Z⎩⎨⎧∉∈===)1,0(,0)1,0(,2)()(2)()('22zzzzPzFzFzPXXZZ12XlY=min{X,2}[]ABCD(D)X.FY(y)Y=min{x,2}R11R12R1R2R21R2259FY(y)=P{Yy}=1P{min{X,2}y}=1P{Xy}P{2y}={}⎩⎨⎧≤2,12,yyyxP=⎩⎨⎧≤2,12),(yyyFXy2,P{Y2}=1;y2,P{Y2}=0,y=2:1)(lim2=+→yFYy,11)2()(lim22-==-→-leFyFYYyy=2FY(y)