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1.A(1)}{=A(2){=A3}(3){=A20002500}(1))},(),,(),,(),,{(--+--+++=Ω)},(),,{(--++=A.(2)X},2,1,0|{LL===ΩkkX}3,2,1,0|{===kkXA.(3)X)},0({∞+∈=ΩX)}2500,2000({∈=XA.2.101101=A{}=B{}=C{5}(1)BAU(2)AB(3)AC(4)AC(5)CA(6)CBU(7)CA-.(1)Ω=BAU(2)ϕ=AB(3)=AC{24}(4)=AC{135678910}(5)=CA{5}={579}(6)==CBCBIU{5}={6810}(7)==-CACA{5}={6810}3.]2,0[⎭⎬⎫⎩⎨⎧≤=121xxA⎭⎬⎫⎩⎨⎧≤≤=2341xxB(1)BAU(2)BA(3)BA(4)BAU.(1)⎭⎬⎫⎩⎨⎧≤≤=2341xxBAU;(2)=⎭⎬⎫⎩⎨⎧≤≤≤=BxxxBAI21210⎭⎬⎫⎩⎨⎧≤⎭⎬⎫⎩⎨⎧≤≤2312141xxxxU;(3)BA⊂ϕ=BA(4)=⎭⎬⎫⎩⎨⎧≤≤=223410xxxABAUU⎭⎬⎫⎩⎨⎧≤≤≤223121410xxxx4.CBA,,(1)ACB,1E(2)BA,C2E(3)3E(4)4E(5)5E(6)6E(7)7E(8)8E(1)CBAE=1(2)CABE=2(3)ABCE=3(4)CBAEUU=4(5)CBAE=5(6)CBACBACBACBAEUUU=6(7)CBAABCEUU==7(8)BCACABEUU=8.5.iAiGeneratedbyFoxitPDFCreator©FoxitSoftware=iiA(1)(2)(3)(4)(2)(1)21AAU(2)321AAA(3)321AAA(4)321AAAUU(5)321321321AAAAAAAAAUU.6.iA={i}3,2,1=i=B{}=C{}iABC321321321AAAAAAAAABUU=323121AAAAAACUU=145531⎟⎟⎠⎞⎜⎜⎝⎛=350nAA⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎠⎞⎜⎜⎝⎛=15245k.39299!2484950!35444535015245)(=××××××=⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎠⎞⎜⎜⎝⎛==nkAP252(1)(2)(3)(4)27=n.(1)(2)(3)(4)DCBA,,,.()A25=Ak492575)(2=⎟⎠⎞⎜⎝⎛=AP()B25×=Bk4910725)(2=×=BP()C252××=Ck4920)(=CP()D57×=Dk754935757)(2==×=DP.36162(1)3(2)356×=n.()334562332×515632=××.()3123322×GeneratedbyFoxitPDFCreator©FoxitSoftware=××.46221(1)2(2)11(3)1(1)(2)(3)CBA,,522562342624)(=××××=⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎠⎞⎜⎜⎝⎛=AP15856224261214)(=×××=⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎠⎞⎜⎜⎝⎛=BPBACU=AB151415852)()()(=+=+=BPAPCP5(1)7(2)5(3)(1)(2)(3)CBA,,,26=n()A)2,5(),5,2(,(1,6),(6,1),(3,4),(4,3)6166)(2==∴AP()B(1,1),(1,2),(2,1),(1,3),(3,1),(1,4),(4,1),(2,2),(2,3),(3,2)185610)(2==∴BP()C(1,1),(1,3),(3,1),(1,5),(5,1);(2,2),(2,4),(4,2),(2,6),(6,2),(3,3),(3,5),(5,3);(4,4),(4,6),(6,4);(5,5);(6,6),18213618)(==∴CP658A35A345××25125345)(3=××=AP.7(1)A(2)B(3)C⎟⎟⎠⎞⎜⎜⎝⎛35(1)53106345!332352312)(==××××=⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎠⎞⎜⎜⎝⎛=APGeneratedbyFoxitPDFCreator©FoxitSoftware(2)103345!33351322)(=×××=⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎠⎞⎜⎜⎝⎛=BP(3)BACU=AB10910353)()()(=+=+=BPAPCP.8xOyxy1=+yx3/1=xAAS2/1||=Ω1859521322121||2=×=⎟⎠⎞⎜⎝⎛-=AS952/118/5||||)(==Ω=ASAP.92.310BA⊂4.0)(=AP6.0)(=BP(1))(AP,)(BP(2))(BAPU(3))(ABP(4))(),(BAPABP(5))(BAP.(1)6.04.01)(1)(=-=-=APAP4.06.01)(1)(=-=-=BPBP(2)6.0)()()()()()()()(==-+=-+=BPAPBPAPABPBPAPBAPU(3)4.0)()(==APABP(4)0)()()(==-=ϕPBAPABP,4.06.01)(1)()(=-=-==BAPBAPBAPUU;(5).2.04.06.0)()(=-=-=ABPBAP11BA,5.0)(=AP7.0)(=BP8.0)(=BAPU)(BAP-).(ABP-)()()()(ABPBPAPBAP-+=U)()()(BPAPABP+=)(BAPU-4.08.07.05.0=-+=.)()()()(ABPAPABAPBAP-=-=-1.04.05.0=-=3.04.07.0)()()()(=-=-=-=-ABPBPABBPABP.1A5.0)(=APB6.0)(=BP8.0)|(=ABP)(ABP)(BAP.4.08.05.0)|()()(=×==ABPAPABP)()()(1)(1)()(ABPBPAPBAPBAPBAP+--=-==UU3.04.06.05.01=+--=210010%10789989981989910090910=×=××××=p.30.580.280.19(1)(2)=A{}=B{}19.0)(,28.0)(,58.0)(===ABPBPAPyxO1/311ΩASh2.3GeneratedbyFoxitPDFCreator©FoxitSoftware(1).327.058.019.0)()()|(===APABPABP(2)678.028.019.0)()()|(===BPABPBAP.45.0)(=AP3.0)(=BP15.0)(=ABP),()|(),()|(APBAPAPBAP==)()|(BPABP=).()|(BPABP=)(213.015.0)()()|(APBPABPBAP====)(5.07.035.07.015.05.0)(1)()()()()|(APBPABPAPBPBAPBAP===-=--==)(3.05.015.0)()()|(BPAPABPABP====)(5.015.05.015.03.0)(1)()()()()|(BPAPABPBPAPBAPABP==-=--==50.30.20.10.40.250.30.1=B{}=1A{}=2A{}=3A{}=4A{}U41==iiBAB25.0)|(1=ABP3.0)|(2=ABP1.0)|(3=ABP0)|(4=ABP.∑==×+×+×==41145.01.01.03.02.025.03.0)|()()(iiiABPAPBP66486(1)(2)(1)=B{}=1A{}=2A{}10/6)|(1=ABP14/8)|(2=ABP70411482110621)|()()|()()(2211=×+×=+=ABPAPABPAPBP(2)1272414)(==BP725%35%40%5%4%2%02.04.004.035.005.025.0×+×+××%45.30345.0008.00140.00125.0==++=80.60.4•-•0.80.2•--0.90.1-•(1)•(2)••=B{•}=A{•}(1))|()()|()()(ABPAPABPAPBP+=52.004.048.01.04.08.06.0=+=×+×=(2)131252.08.06.0)()|()()|(=×==BPABPAPBAP.9CBA,,25%35%40%5%4%2%GeneratedbyFoxitPDFCreator©FoxitSoftware=D{})|()()|()()|()()(CDPCPBDPBPADPAPDP++=02.04.004.035.005.025.0×+×+×=0345.0008.0014.00125.0=++=362.00345.005.025.0)()|()()|(=×==DPADPAPDAP406.00345.004.035.0)()|()()|(=×==DPBDPBPDBP232.00345.002.04.0)()|()()|(=×==DPCDPCPDCP10ABqBPpAP==)(,)()(BAPU)(BAPU)(BAPU.pqqpBPAPBPAPBAP-+=-+=)()()()()(UpqqqpqpBPAPBPAPBAP+-=---+=-+=1)1(1)()()()()(UpqBPAPABPBAP-=-==1)()(1)()(U11BA,)()(,9/1)(BAPBAPBAP==)(),(BPAP.)()(BAPBAP=)()()()(BPAPBPAP=)()()()()()(BPAPBPBPAPAP-=-)()(BPAP=9/1)(=BAP2))(1())(1))((1()()(9/1APBPAPBPAP-=--==3/1)(1=-AP.3/2)()(==APBP121/31/22/3=B{}=1A{}=2A{}=3A{}U31==iiAB.989113121321)()()(11)(32131=-=××-=-=⎟⎟⎠⎞⎜⎜⎝⎛-==APAPAPAPBPiiI13p=A{}=iA{i}6,5,4,3,2,1=i654321AAAAAAAUU=)()()()(654321AAPAAPAAPAP++=)()()()(654321652165434321AAAAAAPAAAAPAAAAPAAAAP+---642)1()1(3)1(3ppp-+---=140.230512.0)8.0()2.0(3523=⎟⎟⎠⎞⎜⎜⎝⎛=p.1510000.21000104.0096.0008.0)2.0(8.023)2.0(3323=+=××⎟⎟⎠⎞⎜⎜⎝⎛+⎟⎟⎠⎞⎜⎜⎝⎛=p.16AA19/27A)(AP.3.1123456GeneratedbyFoxitPDFCreator©FoxitSoftware=iA{Ai}.3,2,1=i)(APp=332131)1(1)(12719pAAAPAPii--=-=⎟⎟⎠⎞⎜⎜⎝⎛==U278)1(3=-p3/1=p.1732%3%5%.1-3=iA{i}.3,2,1=i097.090307.0195.097.098.01)()()(132131≈-=××-=-=⎟⎟⎠⎞⎜⎜⎝⎛==APAPAPA
本文标题:概率统计简明教程答案
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