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(,412008):柱下独立基础是目前房屋建筑中常用的基础型式,在基础设计中,为使这种类型的基础设计得既经济又合理,工程设计人员必须经过多次试算以力学理论为基础,提出了轴心受压单向偏心受压双向偏心受压的柱下独立府面尺寸的直接计算法,为柱下独立基础设计提供了简单而又合理的计算手段:轴心受压;单向偏心受压;双向偏心受压;直接计算法:TU471.11:A:1008-2611(2002)04-0068-03DirectCalculationoftheBotlomSurfaceofIndependentFoundationatColumnFootLIWenke(ZhuzhouMunicipalTransportationTax&FareCollectionDepartment,Zhuzhou412008,China)Abstract:Thebottomsurfaceofthecommonlyusedindependentfoundationoffenchallengingcalcutionsanddemandsmuchofconstructiontechnicianshardwork.Aneffortforanefficientcalculationmethodisthereforeadvancedinthispaper,which,basedonmechaniesandcharacteristicofitsdirectness,iswellsuitableforaxlecenterpressureandbothonewayanddoublewayeccentricpressure.Keywords:axlecenterpressure;onewayeccentricpressure;doubelwayeccentricpressure;directcalculation,,,1,(GBJ7-88)(TJ7-74),(),,,,,,211::P=F+GA,(1):P!f,(2):P∀∀∀(kPa);F∀∀∀(kN);G∀∀∀(kN)G=rGdA,(3)rG,,rG20kN/m3,164Vol.16No.420027JournalofZhuzhouInstituteofTechnologyJuly.2002:2002-03-03:(1965-),,,.A∀∀∀;(A=L#b,L,bm)d∀∀∀(m);f∀∀∀(kPa),(1)(2)(3)(2),:A=Ff-rGd(4):,(=L/b=1),:L=b∃Ff-rGd(5)22,,PmaxPmin:PmaxPmin=F+GA%MxWx,(6):3F+GA+MxWx!1.2f,(7)F+GA!f,(7a),:Pmin=F+GA-MxWX∃0(8):A=L#b=b2,(8a)Wx=162b3,(8b)Mx∀∀∀,X(kN&m),(3)(8a)(8b)(7),:Fb2+6Mx2b3!1.2f-rGd,(9),FMxfrGD,b,,(9)b,,(9)b:b=Ff-rGd,(9a)(9)(9a),:(9a)b,b(9),L=b&,:1)(9)1,,=1;2)(8):Pmin=F+GA-MxWx∃0,:F+GL#b(1-6eoL)∃0eo=MxF+G(9)(9a)L∃6eoL∃6eo,L=6eo,b(9a)L,Pmax=1.2f,Pmin=0,b:(3)12PmaxLb=F+Gb=F+G0.6fL(10),!3,(10),bL/3,b=L/3343:xy:MxMy,:Pmax=F+GA%MxWx+MyWy,(11)Pmin=F+GA-MxWx-MyWy,(11a):A=L#b=b2,(12a)Wx=1/6bL2=1/62b3,(12b)Wy=1/6b2L=1/6b3,(12c)Pmax!1.2f,F+GA+MxWx+MyWy!1.2f,(13)F+GA!f,(13a)(12a)(12b)(12c)(3)(13),:Fb2+6Mx2b3+6Myb3!1.2f-rGd,(14)(14)b,,(14),b694b,Mx,,(9)(9a),b:b=ybo,(15):bo∀∀∀(9a),yMy(9)Mx(9),y1,y=1,y3y=3,(15)b,b(14),,L=b,(14),1,=1,3,=3:,(14)(15),1:F=625kN,Mx=310kN&m,d=1.6,rG=20kN/m2,f=200kPa:,(9)(9a)1)(9a)b=Nf-rGd=652200-20#1.6=1.93m2)b=1.93m(9):Fb2%6Mx2b3!1.2f-rGd,6251.932+6#31021.933!1.2#200-20#1.6,(a)(a):∃1.585,1=1.58533)L=b=1.585#1.93=3.06m4):PmaxPmin=F+GA%Mx16bL2=20#1.6#3.06#1.93+6253.06#1.93%3101/6#1.93#3.062=137.8%102.9=240.7kPa∋1.2f=240kPa,34.9kPa0,,b#L=1.93m#3.06myMy=105kN&m,b,L,,(14)(15)1)b=ybo,bbo=Ff-rGd=625200-20#1.6!1.2#200-20#1.6,(b)(b)y∃1.17,y=1.171,b=y#1.93=2.25m,2)b=2.25m(14)6252.252+6#31022.252+6#1052.253!1.2#200-20#1.6,(c)(c)∃1.42=1.42133)L:L=b=1.42#2.25=320m4):(20#1.6+6253.2#2.25)%6#3102.25#3.22%6#1052.252#3.2=(32+118.8)%80.7%38.9=238.4kPa1.2f=240kPa0.8kPa0(),b#L=2.25m#3.20m2,F=2800kN,Mx=1975kN,d=2.0m,rG=20kN/m3,f=250kPa,::1)b=Ff-rGd=28002500-20#2=3.65m2)b=3.65m(9),28003.652+6#197523.653!1.2#250-20#2=260,(1()(1)):∃1.688,1=1.6883,3)L:L=b=1.688#3.65=5.3m4):(20#2+28005.3#3.65)%1975#63.65#5.32(40+144.7)%115.5=300.2kPa∋1.2f=300kPa,69.5kPa0(),b#L=3.65m#5.3myMy=607.5kN&m,:1)bo=3.65m(9),My=607.5kN&m,2800y3.652+6#60.7523.652!1.2#250-20#2,y∃1.0762,y=1.067213,b=ybo=1.0672#3.65=3.93m2)b=3.93m(14)2800y3.652+6#60.7523.653+6#607.5&3.653!2.60,(2()(2))=1.4773)L:L=b=1.477#3.93=5.7m4):(20#2+28005.7#3.93)%1975#65.72#3.932=(40+125)%92.8%41.4=2.9921.2f=300kPa,30.80(),,,,702002
本文标题:柱下单独基础底边尺寸的直接计算法
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