您好,欢迎访问三七文档
当前位置:首页 > 机械/制造/汽车 > 制造加工工艺 > spss练习题(答案及简要分析)
Spss课程练习题1、某年纪有80名学生,男女生各40人,分成2各班级,下面表1中是某次一门课程的成绩,请分性别、班级计算平均数、标准差等结果。表1性别班级考试成绩男生182,72,74,86,93,74,79,83,78,8184,75,87,78,85,74,84,78,79,83281,77,74,80,70,74,72,90,84,8784,79,77,69,80,79,81,80,88,78女生175,73,89,72,70,74,77,70,61,9185,83,94,85,82,86,91,83,87,77285,83,68,79,82,87,86,81,79,8375,84,73,96,67,88,63,89,71,94CaseProcessingSummaryCasesIncludedExcludedTotalNPercentNPercentNPercent成绩*班级*性别80100.0%0.0%80100.0%Report成绩班级性别MeanNStd.Deviation一班男生80.4500205.33583女生80.2500208.66861Total80.3500407.10561二班男生79.2000205.69025女生80.6500208.87501Total79.9250407.39503Total男生79.8250405.48138女生80.4500408.66159Total80.1375807.208902、10名学生的两门其中考试成绩见表2,请按总成绩的40%计算总分。表2序号(xu)心理统计学(tj)心理学研究方法(ff)总成绩的40%(x)1786958.802659262.803858668.404727659.205689464.806828968.407637053.208877564.809809369.2010778263.603、将表1中的数据合并,即不再分组,试整理成频数分布表,绘制出频数分布图,计算出常用的统计量。Statistics成绩NValid80Missing0Mean80.1375Std.ErrorofMean.80598Median80.5000Mode74.00(a)Std.Deviation7.20890Minimum61.00Maximum96.00Sum6411.00Percentiles2574.25005080.50007585.0000aMultiplemodesexist.Thesmallestvalueisshown成绩FrequencyPercentValidPercentCumulativePercentValid61.0011.31.31.363.0011.31.32.567.0011.31.33.868.0011.31.35.069.0011.31.36.370.0033.83.810.071.0011.31.311.372.0033.83.815.073.0022.52.517.574.0067.57.525.075.0033.83.828.877.0045.05.033.878.0045.05.038.879.0067.57.546.380.0033.83.850.081.0045.05.055.082.0033.83.858.883.0067.57.566.384.0056.36.372.585.0045.05.077.586.0033.83.881.387.0045.05.086.388.0022.52.588.889.0022.52.591.390.0011.31.392.591.0022.52.595.093.0011.31.396.394.0022.52.598.896.0011.31.3100.0Total80100.0100.0成绩95.092.590.087.585.082.580.077.575.072.570.067.565.062.560.0成绩Frequency14121086420Std.Dev=7.21Mean=80.1N=80.004、正常人的脉搏平均数为72次/分。现测得15名患者的脉搏:71,55,76,68,72,69,56,70,79,67,58,77,63,66,78试问这15名患者的脉搏与正常人的脉搏是否有差异?One-SampleTestTestValue=72tdfSig.(2-tailed)MeanDifference95%ConfidenceIntervaloftheDifferenceLowerUpper脉搏频数-1.83614.088-3.6667-7.9494.6161由结果可知,因为0.0880.05,所以在p=0.05的显著性水平上差异不显著5、收集了20名学生的自信心值,见表3,试问该指标是否与性别有关?表3数据值性别(g)1,1,1,1,2,2,1,1,1,2,2,1,2,2,2,1,1,2,2,2自信心(x)6,8,5,6,6,4,8,5,3,8,6,5,5,7,8,5,6,8,7,4IndependentSamplesTestLevene'sTestforEqualityofVariancest-testforEqualityofMeansFSig.tdfSig.(2-tailed)MeanDifferenceStd.ErrorDifference95%ConfidenceIntervaloftheDifferenceLowerUpper自信心Equalvariancesassumed.273.608-.87618.392-.6000.68475-2.03862.83862Equalvariancesnotassumed-.87617.960.392-.6000.68475-2.03885.83885由数据可知,F检验的p=0.6080.05,所以两组样本的方差差异不显著,所以t检验应该是Equalvariancesassumed一项进行判断。双侧t检验的p=0.3920.05,表示两个样本没有显著性差异6、将条件相近的学生配成对,再随机分成两组,采用两种不同的训练方法进行训练,训练一周后,测得两组学生跳高成绩如表4,试问两种训练方法的效果是否相同?表4X1X2151155149151148161141158164141160143139157140153147154142148注:x1、x2表示两组学生的跳高成绩,单位厘米(cm)配对样本T检验:Analyze-CompareMeans-Paried-sampleTTestPairedSamplesCorrelationsNCorrelationSig.Pair1X1&X210.938.000PairedSamplesTestPairedDifferencestdfSig.(2-tailed)MeanStd.DeviationStd.ErrorMean95%ConfidenceIntervaloftheDifferenceLowerUpperPair1X1-X23.20002.85968.904311.15435.24573.5399.006由配对样本相关性检验可知,两样本相关性的p=0.000.05,因此两者存在相关性,由配对样本T检验的数据分析可得,两组数据的p=0.0060.05所以两者之间在0.05的差异水平上差异显著7、为了探讨不同教法对英语教学效果的影响,将一个班级随机分成3组,接受3种不同的教法,英语成绩见表5,试问不同的教法之间是否存在着差异。表5第一组第二组第三组78.0061.0080.0072.0072.0070.0066.0065.0076.0069.0066.0072.0070.0062.0072.00单因素方差分析:因变量:英语成绩;自变量:教法;3种不同的水平:3种不同的教法Analyze-CompareMeans-One-WayANOVATestofHomogeneityofVariances成绩LeveneStatisticdf1df2Sig..007212.993ANOVA成绩SumofSquaresdfMeanSquareFSig.BetweenGroups200.1332100.0675.488.020WithinGroups218.8001218.233Total418.93314MultipleComparisonsDependentVariable:成绩(I)组数(J)组数MeanDifference(I-J)Std.ErrorSig.95%ConfidenceIntervalLowerBoundUpperBoundLSD第一组第二组5.80002.70062.053-.084111.6841第三组-3.00002.70062.288-8.88412.8841第二组第一组-5.80002.70062.053-11.6841.0841第三组-8.8000(*)2.70062.007-14.6841-2.9159第三组第一组3.00002.70062.288-2.88418.8841第二组8.8000(*)2.70062.0072.915914.6841*Themeandifferenceissignificantatthe.05level.由方差分析的结果可知,组间的F检验的p=0.0200.05,所以组间差异在0.05的水平上差异显著,由事后检验结果可得第二组和第三组的p=0.0070.05,因此第二组和第三组在0.05的水平上差异显著。8、4名工人操作3台机器,1天的日产量数据见表6,试问机器之间、工人之间在日产量上是否有差异表6工人1234机器150474753263545758352424148双因素方差分析(无交互作用):因变量,日产量;自变量,机器,有3个水平;工人,有4个水平Analyze-GeneralLinlearModel-UnivariateTestsofBetween-SubjectsEffectsDependentVariable:日产量SourceTypeIIISumofSquaresdfMeanSquareFSig.CorrectedModel433.167(a)586.63315.831.002Intercept31212.000131212.0005703.716.000机器号318.5002159.25029.102.001工人号114.667338.2226.985.022Error32.83365.472Total31678.00012CorrectedTotal466.00011aRSquared=.930(AdjustedRSquared=.871)机器号MultipleComparisonsDependentVariable:日产量(I)机器号(J)机器号MeanDifference(I-J)Std.ErrorSig.95%ConfidenceIntervalLowerBoundUpperBoundLSD1.002.00-8.7500(*)1.65412.002-12.7975-4.70253.003.50001.65412.079-.54757.54752.001.008.7500(*)1.65412.0024.702512.79753.0012.2500(*)1.65412.0008.202516.29753.001.00-3.50001.65412.079-7.5475.54752.00-12.2500(*)1.65412.000-16.2975-8.2025Basedonobservedmeans.*Themeandifferenceissignificantatthe.05level.日产量机器号NSubset12Student-Newman-Keuls(a,b)3.00445.75001.00449.25002.00458.0000Sig..0791.000Meansforgr
本文标题:spss练习题(答案及简要分析)
链接地址:https://www.777doc.com/doc-5481196 .html