教师招聘考试小学数学教师专业知识大全

112345112{y|y=x2}{(xy)|y=x2}y3N+={0123}212=ABABABAB31AB={x|xAxB}AB={x|xAxB}CUA=x|xUxAU2ABC=ABACCUAB=CUACUBCUAB=CUACUB412pqpqp3pqqppqpqpqpqpppp3qppqqpqp521pqpqqpqppqpq2pAqqABpqBApqA=Bpq3pq671M={y|y=x2+1xR}N={y|y=x+1xR}MNMNM={y|y=x2+1xR}={y|y1}N={y|y=x+1xR}={y|yR}MN=M={y|y1}MN{y|y=f(x)xA}y=f(x){xy|y=x2+1xR}y=x2+1{y|y1}={x|x1}2A={x|x2-3x+2=0}B+{x|x2-mx+2=0}AB=BmA={12}AB=BBABB=B={1}{2}B={12}B==m2-8022m22B={1}{2}02m2402m10mB={12}221m21m=3m=322m22B={1}{2}=03xyRx+y2xy1x1y1x+y2x+y23xy1pqpqpqqpqpq4ABCBDCDADCBADADA5ax-y+b=012x-2y-3=023x-5y+1=001y5x303y2x212P411,417P0b411417a17a+4b=11ab17a+4b=114a1711b04a1711yax0)417x(a)411y(0417x,0411y411,4171241M={x|x2+x+2=0}a=lg(lg10){a}MA{a}=MBM{a}C{a}MDM{a}2U=RA={x|x-a|2}B={x|x-1|3}AB=aA[02]B-22C02]D023M={x|x=a2-3a+2aR}N{x|x=b2-bbR}MNAMNBMNCM=ND4A={x|xZ-10x-1}B={x|xZ|x|5}ABA11B10C16D155M={12345}A15B16C31D326ABCD7coscosABCD8A={x|x=3k-2kZ}B={y|y=3+1Z}S={y|y=6m+1mZ}ASBABS=BACSB=ADSB=A9mx2+2x+1=0A0m1m0B0m1Cm1Dm110px2+ax+b=0qabpqABD11M={Z24m|m}N={x|}N23xMN=__________121006065________13x|x|-|x-1|=a________________14ab=0ab____________15p1p{12345}2ap6-app__________516A={(xy)|y=ax+1}B={(xy)|y=|x|}ABa17Cy=-x2+mx-1M03N30CMN18A={x|x2+px+q=0}M={13579}N={14710}AM=AN=Apq1921xa2b=2-xc=x2-x+1abc17211ABAaBbABfABfb=f(a)AB2ABAC={f(x)|xA}210)x(f)x(f1)x(f)x(ff(x)0623f(x)f(a-x)=f(a+x)f(b-x)=f(b+x)abT=2|a-b|4f(x)f-1(x)f(x)f-1(x)f(x)f(x)ACf-1[f(x)]=xxAf[f-1(x)]=xxC84511x3x2)x(fy=g(x)y=f-1(x+1)y=xg(11)y=g(x)y=f-1(x+1)g(x)f(x)y=f-1(x+1)x+1=f(y)x=f(y)-1y=f-1(x+1)y=f(x)-1g(x)=f(x)-1g(11)=f(11)-1=237f(x)b=f(a)a=f-1(b)2f(x)-+xRf(x)+f(x+2)=0-1x1f(x)=2x-11x3f(x)f(x)+f(x+2)=0f(x)=-f(x+2)xRx-2xf(x-2)=-f[(x-2)+2]=-f(x)1x3-1x-21f(x-2)=2(x-2)-1=2x-5f(x)=-f(x-2)=-2x+5f(x)=-2x+51x33g(x)=-x2-3f(x)x[-12]f(x)f(x)+g(x)f(x)f(x)f(x)=ax2+bx+ca0f(x)+g(x)=(a-1)x2+bx+c-3f(x)+g(x)03c01a3c1af(x)=x2+bx+3f(x)[-12]b4b3)2bx()x(f222bx12b2b-4f(x)[-12]7b2)2(f))x(f(min82b+7=1b=322b-12-4b234b)2b(f))x(f(2min134b222b32b-1b2f(x)[-12](f(x)min=f(1)=4-b4-b=1b=33x2x)x(f23x3x)x(f34Ry=f(x)f(0)0x0f(x)1abRf(a+b)=f(a)f(b)1f(0)=12xRf(x)03f(x)R4f(x)f(2x-x2)1x1a=b=0f(0)=[f(0)]2f(0)0f(0)=12a=xb=-xf(0)=f(x)f(-x))x(f1)x(fx0f(x)109x0-x0f(-x)00)x(f1)x(fx=0f(0)=10xRf(x)03x2x1f(x2)0f(x1)0x2-x101)xx(f)x(f)x(f)x(f)x(f121212f(x2)f(x1)f(x)R4f(x)f(2x-x2)=f[x+(2x-x2)]=f(-x2+3x)1=f(0)f(x)Rf(3x-x2)f(0)3x-x200x3f(a+b)=f(a)f(b)abfx5lgx+lgy=2lg(x-2y)yxlog2xy2)y2x(xy0y2x0y,0xx=4y4yx44logyxlog22612311.21.3yxy=abx+cabc41.37f(x)=px2+qx+rp0103.1rq3p9)3(f1rq2p4)2(f1rqp)1(f7.0r35.0q05.0pf(4)=-0.0542+0.354+0.7=1.3g(x)=abx+c3.1cab)3(g2.1cab)2(g1cab)1(g324.1c5.0b8.0ag(4)=-0.80.54+1.4=1.35|1.35-1.37||1.3-1.37|y=-0.8(0.5)x+1.41Rf(x)f(x+1)=-f(x)[-10]a=f(3)b=f(2)c=f(2)abcAabcBacbCbcaDcba2x)2x(logaa0a1A0B1C2D33|x1|)31(yA-1B1+C--11+D-+9)12x4x(logy22111A-3]B--3]C-3+D3+10y=log2|ax-1|abx=2aA21B21C2D-2624A3B4C6D127Rf(x)f(x+2)=-f(x)0x1f(x)=x)215(f=__________8y=loga(2-x)xa__________9f(x)[13]f(x2+1)__________10f(x)=x2-bx+cf(1+x)=f(1-x)f(0)=3f(bx)f(cx)__________11f(x)=log3x+3x[19]y=[f(x)]2+f(x2)__________12A={y|y=x2-4x+6yN}B={y|y=-x2-2x+18yN}AB__________13(x)g(x)f(x)=m(x)+ng(x)+20+f(x)-0__________14y=log2(x2+1)x0__________15bcacabcbcabaxx11xx11xx11=__________16cx1ax)x(f2[-15]ac17[-22]f(x)[02]f(1-m)f(m)m180a1y=logaxx1ABCtt+2t+41ABCSS=f(t)2S=f(t)3S=f(t)19f(x)=122axxR1af(x)-+2f(x)a123f(x)kkx1log)x(f21200a1f(x)=3x3xloga[mn][logaa(n-1)logaa(m-1)]1m32a11n2n1an=f(n)nN+nnSnSn=a1+a2+anSn2nSS1nSa1nn1nanSn,Sn21{an}an+1-an=dnN+2an=an-1+an+1n2nN+2an=an+(n-1)dan=am+(n-m)dn2)aa(nd2)1n(nnaSn11n3an=an+bannaSn=an2+bnSnn{an}{bn}{annn},{k1ika},{kan+c}kcm+n=p+qam+an=ap+aqa1+an=a2+an-1=a3+an-2=2n=p+q2an=ap+aqnS2n-1=(2n-1)anS=21naS=21na3131n1naa=qqan0an2=an-1an+1n2nN+2an=a1qn-1an=amqn-m;n1qq1qaaq1)q1(a1qnaSn1n11n3m+n=p+qaman=apaqa1an=a2an-1=a3an-2=2n=p+qan2=apaq{kan}{k1iia}4123{an}{naa}a0a1{an}{logaan}a0a11{an}d01ka2kankak1=1k2=5k3=17k1+k2++kn{an}a1da1a5a17a52=a1a17a1+4d2=a1(a1+16d)a1=2dq3ad4aaaq1n15nka1nn1ka21kd)1k(aan1n11n1k3aqaan132k1nn14n)331(2)132()132()132(kkk1n1n10n211n3nk1+k2++kn{kn}{kn}2{an}Sn{an}nS7=7S15=75,Tn{nSn}nTn{an}a1d75d21415a15S7d267a7S115171d2a12)1n(n2Sn252n21n2nSnn{nSn}n4an41T2n{an}Sn=An2+Bn75B1515AS7B77AS2152725B21An25n21S2nn3{an}nSn1aS2nn1{an}1521nnnaa1b{bn}nBnBn21.IanSnan=Sn-Sn-1n21aS2nn4Sn=(an+1)24Sn-1=(an-1+1)2n24(Sn-Sn-1)=(an+1)2-(an-1+1)24an=an2-an-12+2an-2an-1(an-1+an)(an-an-1-2)=0an0an-an-1=2{an}21aS2nnn=1a1=1an=2n-1II)1n211n21(21)1n2)(1n2(1bn21a2121)a1a1(21)]a1a1()a1a1()a1a1[(21B1n1n11nn3221n4Sn=(an+1)24Sn-1=(an-1+1)2n-1n+1nnn4{an}m77m33a1-am=18m=2n-1nN+33a)1n(S77a)1n2(Snn1n233771n1n2n=4m=7an=11