化工原理第三版陈敏恒课后习题答案全解(清晰、可打印版)

11.pa=101.3kPa,=1000kg/m3,i=13600kg/m3,R=120mm,H=1.2mPAPaPAPa1-2-3PA=P1+g(H-R)P1=P2=P3P3=Pa+iRgPA=Pa+iRg+(H-R)gPA=PA-pa2.R=130mm,h=20cm,D=2m,=980kg/m3,i=13600kg/m3W(1)u=0(2)Hg=RigW=41D2(H+h)3.T=20=880kg/m3,H=9m,d=500mm,h=600mm(1)FN(2)PPa(1),F2F=PA=g(H-h)41d2(2)P=gH4.HS=500mm=780kg/m3,=1000kg/m3HmHSg=Hgρρ⋅=∴SHH5.i=13600kg/m3,=1000kg/m3,h1=1.2mh2=0.3mh3=1.3mh4=0.25mPAB(Pa)PA-PC=(h1-h2)(i–)gPC-PB=(h3-h4)(i–)gPA-PB=(h1-h2+h3-h4)(i–)gZA=ZBPAB=PAB6.D=9mm=10tP,h3P0mg)PP(D402=−π024PDmgP+π=ghPP0ρ⋅∆+=7.P()=82kPaPa=100kPaP()HP()=Pa-P()P()+gH=Pa8.A=B=i(1)RH(2)PAPB4(1)PA-PB=R(i–)g=H(i–)g(2)iPA-PB=H(i–)g0PAPBPA+ZAgPB+ZBgPAPB+(ZB-ZA)gPB9.22112aBDdhg)(hgPPρρρ−−−=1-1ghghPghP21B1aρρρ+∆+=+122d4hD4hππ⋅=⋅∆22Ddhh⋅=∆1ghgDdhPghP2122B1aρρρ+⋅+=+10dp=(Xdx+Ydy+Zdz),Ph=0=Pa,T=const,hX=0Y=0Z=-gdz=dhdp=-gdhRTpM=ρMR5111144.5mmP=2MPa()T=20qV0=6300m3/h()uqmG1Pqv=nRT100101PPTTqqVV××=∴2141dquVπ=∴(2)RTpM=ρρ⋅=∴uG(3)4.22290=ρ00Vmqq⋅ρ=12qV=60m3/hdA=100mm,dB=200mm,hAB=0.2m,i=1630kg/m3,=1000kg/m3,(1)R=(2)(1)AB2222BBAAuu+=+ρρPP)(222ABBAABuu−=−=∴ρPPPPBA=Rg(i-)(2)uAuBPBAPBA=Rg(i-)R13d=200mm,R=25mm,i=1000kg/m3=1.2kg/m36qV(m3/h)1-22ugzP2ugzP22222111++=++ρρP1=Paz1=z2u1=0222au2PPρ=−UPa-P2=Rg(i-)()22241duqVπ⋅=∴14H=0.8mh=0.6mD=0.6md=10mmCO=0.620.5m1-22ugzP2ugzP22222111++=++ρρP1=P2=Paz2=0,z1=H-h=0.8-0.6=0.2m,u1=0)(22hHgu−=∴u0=C0u20.5mh=0.6m702245.04udD×π×π=τ∴15qv=3.7710-3m3/s,d=40mm,D=80mm,R=170mm,=1000kg/m3Hf(J/N)1-21222221122fhuu++=+ρρPPP2-P1=Rg(-i))(2122212112uuhf−+ρ−=∴PPghHff=1630d1=20mm,d2=36mmhf,Pmin30PV122ugzP2ugzP22222111++=++ρρP1=P2=Pau1=0,z2=08122gzu=∴11-2,2ugzP2ugzP2xxx211a++=++ρρu1=0ρ+−ρ+=∴)]2ugz()Pgz[(P2xxa1xminx2xxa1PP2ugz)Pgz(=++ρ17P1-P2A1A2,hfu1u212221212222211AA2uP2uP2uP+=+=+ρρρ−=−∴1AA2uPP2212121ρ)AA()PP(2Au22212121−−=ρ1212uAAu=18P2=Paqv=0.025m3/sd1=80mm,d2=40mm,P1=0.8MPa,=1000kg/m3(N)9FP1A1-F-P2A2=qv(u2-u1))m/N(10013.1P)m/N(10013.910013.1108.0P25225561×=×=×+×=F=P1A1-P2A2-qv(u2-u1)192uAA1h21221f⋅−=Fn=P1(A2-A1)211222n2211uAuAFAPAPρρ−=+−Fn=P1(A2-A1)u1A1=u2A2P2-P1=u2(u1-u2)1-12-2f22222111h2ugzP2ugzP+++ρ=++ρz1=z22)uu(2uu)uu(u2uuPPh2212221122222121f−=−+−=−+−=ρ20dj=0.04m,uj=20m/s,us=0.5m/s,D=0.1m,1P1212(1)u2(2)UR10(1)vjvs2vqqq+=)(422jsvsdDuq−π⋅=24jjvjduqπ⋅=222AquV=∴(2)12,svsjvj22v21uququqA)PP(ρρρ−−=−gPPRgRPPii)()(1212ρρ−=∴ρ−ρ=−−21u=0.8m/sD=100mmd=99.96mmL=120mm=100mPaSFdyduµ=τ∴=D-d/2=(100-99.96)/2=0.02mmd,=const,constdydu=µτ=11δ−−=∆∆=00uyudydudLdyduAFπ⋅µ=⋅τ=22qvab=3.5mld0=1mmab=80s,νbc1atmab,AquVabτ=bcPb=Pc=PaZbg=Zcg+hf2bc2bcbcdZu32duZ32gZνρµ==ugd322=ν∴ν=udRe2371maxRr1u/u−=12maxu/u1(2)Ardr2uAudAuR0Aπ⋅==∫∫x=R-rdr=-dx)271)(171/(u2)Rx(d)Rx1()Rx(u2)dx)(xR()Rx(Ru2rdr2)Rr1(uR1Ardr2uumax7110max0R712max71maxR02R0++=−=−−⋅=π⋅−π=π⋅=∴∫∫∫∫))((2)(1)(107323max33dxxRRxRuudAuAuRA−−π⋅π⋅==α∫∫24,,,B,H,µδρ3gBq3v=HBy(yBH)g-BH=0=ygdyduµτ−=dydugyµρ−=∴13dugydyu0y∫∫−=ρµδuBdyudAqAv∫∫δ==025H=3m,d=50mm,=0.2mm,l=8m,90qv=20m3/hT=20(1)P(2)qv,P(1)1-2f22222111h2ugzP2ugzP+++ρ=++ρP1=Pa,z1=0,z2=H=3m,u1=04)2((22222dquhuHgPPPVfaπ=ρ++=−=∑+=2u)dl(h22fζλ502.0/Re=εµρ=ddu14=1090=0.75=10.75(2)ρ)h2ugH((Pf22++=qVuhfP26d1=50mm,l1=80m,905d2=40mm,l2=20m,1/2T=20()qv=310-3m3/sZ1-212f2222211h2ugzP2ugzP+++=++ρρP1=P2=Pa,z2=0,z1=Z,u=012f22h2uZg+=∴21141dquVπ=22112)(dduu=20µ=1mPaS=0.2mmµρ=111Reudµρ=222Reud402.0/2=εd502.0/1=εd1290=0.75,1/2=4.51=0.52=0.18gudlgudlguZ2)(2)(222222221111122∑∑ζ+λ+ζ+λ+=∴1527qv=0.10m3/min383mmH=10m,l=20m,()890=1830kg/m3,=12mPaSP(MPa)1-212f22222111h2ugzP2ugzP+++=++ρρP1=P1-pa=P1-P2,z1=0,z2=H,u1=0)ld(2ugHP2u)d(h222221f+ζ+λρ+ρ=∴ζ+λ=−ll28=30mPaS,=900kg/m3,d=40mm,l1=50m,l2=20m,P1()=0.09MPa,P2=0.045MPa,1/4,le=30m(1)qv(2)P1P2(1)Z=0PA=Pa+P1PB=Pa+P21/4A-B16fBBAAhuuΣ++=+2222ρρPP0uuBA==2udh2f⋅Σλ=Σlud64ρµλ=ρµρρ232duBA⋅Σ+=lPP232duBAlΣµ−=∴PPµρ=udRe(2)u2)P211udlAζλρρ++=PPAP1222222udlPuB⋅+=+λρρPl21dl2λ29T=20H=5m,P1=P2=Pa323mm=0.05mm,l=100mqV2udl2ugzP2ugzP222222111⋅+++=++λρρP1=P2=Pau1=u2=0z1=H,z2=0002.02605.0d/2udlgH2==⋅=∴ελ=0.02317lgHduλ=∴2T=20=880kg/m3,=0.67mPaSµρ=udRelgHduλ=230d=2m,/d=0.0004,=0.67kg/m3=0.026mPaS,qv=80000m3/h,air=1.15kg/m3P1=0.2kPaH1221f22222111h2ugzP2ugzP−Σ+++=++ρρd1=d2,u1=u2z1=0,z2=HP1=Pa-P1P2=Pa-airgH2udHh221f⋅⋅λ=Σ−241dquvπ=µρ=udRe/d=0.0004,181-22(21udHgHgHPair⋅λ++ρρ−=ρ−P10H,P1,31A=3m2,h=2m,H0=4m,l=10m,=0.022,323mmH=1m=?1-12-221f22222111h2ugzP2ugzP−Σ+++=++ρρP1=P2,z1=0,z2=-Hu1=02udlh2f⋅=ΣλgudlH2)1(2λ+=τ⋅π⋅=⋅−dduAdH24132qv=2.510-3m3/s,P()=0.2MPaH=6m,=1100kg/m3,403mm,L=50m,=0.024He(J/N)19g2udlg2uzgPHeg2uzgP222222111⋅+++=+++λρρP1=Pa,P2-Pa=0.2MPa,Z2-Z1=6m,u1=u2=033ZAA’=6mdBC=600mm,lBC=3000m,dCD=dCE=250mm,lCD=lCE=2500mm,=0.04,qVqV=qVBC=qVCD+qVCEu1d12=u2d22+u3d32hf2=hf3323223332222,22ddlludludl==⋅=⋅∴λλ2211232)(2dduuuu==AA’1212122421211122222111'41])(41[222udqudlddudlggudlgudlZvAA⋅π=+λ=⋅λ+⋅λ=34lAB=6m,d1=41mm,lBC=15m,lBD=24m,d2=d3=25m,=0.03(1)qV1qV2qV3(2)DqV3’20(1)B2uh2uh233f222f+=+2u)1dl(2u)1dl(23332222+=+λλqV1=qV2+qV3u1d12=u2d22+u3d32C2u2udl2udlHg2323332111+⋅+⋅=λλ2DqV1’=qV3’,d'ud'u233211⋅=⋅C2u2udl2udlHg2323332111+⋅+⋅=λλ35dB=dC=20mm,lB=2m,lC=4m,=0.028(1)B=C=0.17qVB/qVC(2)HB=C=24q’VB/q’VC(3)21(1)02uh2uh2CfC2BfB+=+2u)1dl(2u)1dl(2CCCC2BBB