１６.2.3 整数指数幂(1)

16．2．3整数指数幂（1）知识领航：任何一个不等于零的数的零次幂等于1，即)0(10aa当n为正整数时，nnaa1（)0a正整数指数幂运算性质也可以推广到整数指数幂．e线聚焦【例】计算：（1）3223yx，（2）3322232nmnm.分析：可先运用幂的运算性质进行计算，再化成正整数指数的形式．解：（1）3223yx=323233yx=66271yx=6627xy.（2）3322232nmnm=334434nmnm=112mn=nm12.双基淘宝◆仔细读题，一定要选择最佳答案哟！1．若m,n为正整数,则下列各式错误的是（）A．nmnmaaaaB.nnnbabaC.mnnmaaD.nnamam12.下列计算正确的是()A.110B.15.0210C.111D.235xxx3.若25102x,则x10等于()A.51B.51C.501D.62514.若31aa,则22aa等于()A.9B.1C.7D.115已知px21,py21,则用x表示y的结果是()A.11xxB.12xxC.1xxD.x26.计算:12211nn=______________(n为整数)7.计算:____________2218.化简:))((2211yxyxyx=______________9.已知:57,37nm,则nm27________________.10.已知:9432827321xx,则x=_____________综合运用◆认真解答,一定要细心哟!11.计算:(1)10123)326(34(2)32132xyba(3)111)(2babaab(4)42318521qpqp(5)321232223yxcba(6)23323322　12.已知:axx1,求22xx和44xx的值拓广创新◆试一试，你一定能成功哟！13.求满足2151691089cba的一切整数a,b,c的值.