【高教版】中职数学拓展模块：3.1《排列与组合》优秀教学设计

(mn)nmPmn.Amn234342(90)*310*1N.k1k2nknN=1k+2k++nk3.12N1k12k2nknnN=1k2knk3.2332.31321232=66.15*32.nm(mn)nmmnmn.20*14a,b,c,d211*nm(mn)nmPmn.14a,b,c,d224P24P12Pmnm31123m31n11nn112n1n213n3mnm11mnm+1n(n1)(n2)(nm+1)nm(mn)PmnPmn=n(n1)(n2)(nm+1)3.*mnNmn3.3=n3.3Pnn=n(n1)(n2)321.3.41nnn!.0!1n!=n(n1)(n2)321.3.4Pnn=n!3.5P(1)(2)mnnnnnm(-+1)(1)(2)(1)21=()21nnnnmnm!)!nnmmn3.3!P)!mnnnm3.640*225P44P25P=54=2044P44321243733133.5337P765210210(98)648455*.44SHIFT!x=24.4=24..36P6SHIFTPrn3=120.36P=120.60*1.12nP=56n=.212345.2.ABCD65*nm(mn)mnP70=n(n1)(n2)(nm+1)*75*1234585*(1)(2)3131(3)90(90)*31*332nmmnnm32nmmnmnmmnm015*nmmnnmCmn34C34P134P=4322434334C3!3344C3!PnmmnP(1)(2)...(1)C3.7P!mmnnmmnnnnmm!P()!mnnnmPCPmmmnnm!C3.8!()!mnnmnm*,nmNmn1CCmnmnnmnm2nCnmnCmn18201822020202019CCC1902!211CCCmmmnnnmn2mn35*53474CC05C343777P765CC353!3!=!4!055!5!C10!(50)!5!0C1C1nnn610103310C1203!1203738333650*26C6SHIFTnCr,2=1526C=1560*1127C245C338C41012C2633571165*70(mn)CmnP(1)(2)...(1)CP!mmnnmmnnnnmm*75*163235385*(1)(2)3131(3)90(90)*311*7521212554C1021225P542081003123331100321001009998C161700321221982.1182989897CC29506213333310098CC1617001520969604*1812222097311*70*75*108231323133185*(1)(2)3131(3)90