三绕组变压器运行方式损耗计算及经济性分析

2820063J���nal�fH��h��Teache��C�llegeV�l.28Ma�.�2006*(�313000)���������.����TM401�A�10091734(2006)S00105060���.��1�.��.���������.�������.1�c���2�c���3���P=PO+S21(RK1+C22RK2+C23RK3).(1)(1)�PO�S1�RK1=PK1S21N�RK2=PK2S22N�RK3=PK3S23N��(��kV2).C2+C3=1.(2)�C2=S2S1�C3=S3S1�.(2)(1)��PC2�P=�(C2).�d�PdC2=0�CJ2�CJ2=RK3RK2+RK3.(3)*�20051030�(1977-)�����.�CJ3�CJ3=RK2RK2+RK3.(4���.�.�PJ��PJ=PO+S21RK1A+P2K3RK2+P2K2RK3(PK2+PK3�(�2.21�1A�B�c���2A�c���3A�c���2B�c���3B���C2A=S2AS2A+S3A=S2AS1A�C3A=S3AS2A+S3A=S3AS1A�C2B=S2BS2B+S3B=S2BS1B�C3B=S3BS2B+S3B=S3BS1B�C2A+C3A=1�C2B+C3B=1.�D1A.=S1AS1A+S1B=S1AS1��D1B.=S1BS1B+S1B=S1BS1�.D1A.+D1B.=1�S1�=S1A+S1B.A�B��PA.B��PA.B=POA+POB+S21��D21A(RK1A+C22ARK2A+C23ARK3A�+D21B.(RK1B+C22BRK2B+C23BRK3B��.(5��RK1A�RK2A�RK3A�RK1B�KK2BRK3BA�B.�RK1A.=PK1AS21NA�RK1B=PK1BS21NB�RK2A=PK2AS22NA�RK2B=PK2BS22NB�RK3A=PK3AS23NA�RK3B=PK3BS23NB.60128PK1A�PK2A�PK3A�PK1B�PK2B�PK3BA�B��.(5����D1A�D1BC2A�C3A�C2B�C3B.(5��S1���PA�BD1A��PA�B=�(D1A����(5�d�PA�BdD1A�=0�A�B(��DJ1A=RK1B+C22BRK2B+C23BRK3BRK1A+C22ARK2A+C23ARK3A+RK1B+C22BRK2B+C23BRK3B�DJ1B=RK1A+C22ARK2A+C23ARK3ARK1A+C22ARK2A+C23ARK3A+RK1B+C22BRK2B+C23BRK3B�(6�DJIADJIB=RK1B+C22BRK2B+C23BRK3BRK1A+C22ARK2A+C23ARK3A.(6��A�B�PJA.B.�(3��(4�A�BCJ2A�CJ2B�CJ3A�CJ3B�CJ2A=PK3APK2A+PK3A�CJ3A=PK2APK2A+PK3A�CJ2B=PK3APK2B+PK3B�CJ3B=PK2BPK2B+PK3B.�A�B�PJA�B��PJA.B=POA+POB+S21�D2JIARK1A+P2K3ARK2A+P2K2ARK3A(PK2A+PK3A�(�2+D2J1BRK1B+P2K3BRK2B+P2K2BRK3B(PK2B+PK3B�(�����2.3���2�I�2A=(I2�Z12B+I3BZ1B-13AZ1A��(Z12A+Z12B��(7�I�2B=(I2�Z12A+I3AZ1A-13BZ1B��(Z12A+Z12B�.(8�(7��(8���S�2A=S2�UK12B%UK12A%+UK12B%+S3BUK1B%-S3AUK1A%UK12A%+UK12B%.S�2B=S2�UK12A%UK12A%+UK12B%-S3BUK1B%-S3AUK1A%UK12A%+UK12B%.�UK12A%�UK13A%�UK23A%�UK12B%�UK13B%�UK23B%A�B���UK1A%�UK2A%�UK3A%�UK3A%�UK1B%�UK2B%�UK3B%A�B��.�C2�=S2�S1��C3�=S3�S1��D3A=S3AS3A+S3B=S3AS3��D3B=S3BS3A+S3B=S3BS3��7012006�C2�+C3�=1�D3A+D3B=1.(9)�B=UK1B%UK12A%+UK12B%��A=UK1A%UK12A%+UK12B%��B=UK12B%UK12A%+UK12B%��A=UK12A%UK12A%+UK12B%��B+�A=1��=C3�D3BUK1B%-C3�D3AUK1A%UK12A%+UK12B%=C3�D3B�B-C3�D3A�A�S�2A=(�BC2�+�)S1��S�2B=(�AC2�-�)S1�.(10)��.�.�=0�S�2AS�2B=�B�A=UK12B%UK12A%��.A�B��P�AB��P�AB=POA+POB+S21��C23�(D23ARK3A+D23BRK3B)+(�BC2�+�)2RK2A+(�BC2�+�+C3�D3A)2RK1A+(�AC2�-�)2RK2B+(�AC2�-�+C3�D3B)2RK1B�.�.�P�ABD3A�P�AB=�(D3A)�DJ3A��P�AB�P�JAB�d�P�ABdD3A=0�DJ3A�DJ3A=C3�(RK3B+�BRK2A+�BRK2B)+C2�(�BRK2A-�ARK2B)C3�(RK3A+RK3B+RK2A+RK2B).(11)�UK1%UK2%�UK3%UK2%UK2%�0�UK1%�UK12%�UK3%�UK23%.�(10)�S�2A=S1��2-S3A.S�2B=S1��2-S3B.�����.43��S3A=S2�(�U1B%-�U12B%)+S3�(�U13B%-�U1B%)��-�2�S3B=S2�(�U1A%-�U12A%)+S3�(�U13A%-�U1A%)��-�2.(12)S2A=S2�(�U12B%-�UK1B%)-S3�(�UK1A%-�UK13A%)��-�2�S2B=S2�(�U12A%-�U1A%)-S3�(�U1B%�-U1K13B%)��-�2.(13)��=UK1A%+UK1B%��=UK12A%+UK12B%��=UK13A%+UK13B%.��80128.�.55.1�D2AD2B�D2A=S�2AS2�=�BC2�+�C2��D2B=S�2BS2�=�AC2�-�C2�.D2A�D2B��D2A�=C2A�D1A�C2��D2B�=C2BD1B.C2�.(14)DJ2ADJ2B�DJ2A=C2ADJ1AC2ADJ1A+C2BDJ1B�DJ2B=C2BDJ1BC2ADJ1A+C2BDJ1B.�PA�BD1A.�(13)�PA�B�2A..���DJ2A-D2A����DJ2A-D2A����DJ2A-D2A.���DJ2A-D2A��.5.2�AD3A�D3A=S2�(�U1B%-�U12B%)+S3�(�U13B%-�U1B%)S2���(U1B%+U1A%)-�(U12B%+U12A%)�+S3���(U13B%+U13A%)-�(U1B%+U1A%)�.(9)�AD3A�(11)ADJ3A���DJ3A-D3A.���DJ3A-D3A����DJ3A-D3A���DJ3A-D3A���.6110kV.110kV1..�(288)�.110kV�2��0.95.#235kV�.1110kV#1#2SN(MVA)31.531.5P0(KW)47.134PK12(KW)169.47197.53PK13(KW)183.73174.78PK23(KW)135.73120.42UK12%10.2510.6UK13%18.3518.3UK23%6.586.89012006�2110kV#1#235kV(MVA�-2.996.7210kV(MVA�16.165.35���(10��S�2A=-3.80MVA�S�2B=7.53MVA.�D2A=-3.803.73=-1.02�D2A=-2.993.73=-0.80�DJ2A=-0.40.�DJ2A-D2A���DJ2A-D2A��.�(12��(13���S2A=2.04MVA�S2B=1.68MVA�S3A=10.63MVA�S3B=10.87MVA.�D3A=10.6321.51=0.49�D3A.=16.1621.51=0.75�DJ3A=0.45.�DJ3A-D3A.���DJ3A-D3A�.����P=143.5(KW���P�=145.0(KW���P=133.6(KW�.��.7(1��32���.�.��3.(2�UK1%�UK12%�UK3%�UK23%�.(3��.��1�.�M�.��1999.�2�.�J�.�2004�(1��50�51.�3�.�J�.�2004�(4��23�28.�4�.�J�.�2001�21(4��49�52.01128